Re: VolanoMark regression with 2.6.27-rc1

From: Peter Zijlstra
Date: Wed Aug 20 2008 - 17:04:31 EST


On Wed, 2008-08-20 at 13:58 -0700, Ray Lee wrote:
> On Wed, Aug 20, 2008 at 1:30 PM, Peter Zijlstra <a.p.zijlstra@xxxxxxxxx> wrote:
> > Nick is right, try:
> >
> > int main(int argc, char **argv)
> > {
> > unsigned int x = 7, y = 5;
> > printf("%d\n", avg(x,y));
> > return 0;
> > }
> >
> > It fails because 5-7 = -2, which needs a signed division or sign
> > extending right shift.
> >
> > we'd need something like:
> >
> > #define avg(x, y) ({ \
> > typeof(x) _avg1 = (x); \
> > typeof(y) _avg2 = (y); \
> > (void) (&_avg1 == &_avg2); \
> > _avg1 + (signed typeof(x))(_avg2 - _avg1)/2; })
> >
> > except that typeof() doesn't work that way.
> >
> > #define avg(x, y) ({ \
> > typeof(x) _avg1 = (x); \
> > typeof(y) _avg2 = (y); \
> > (void) (&_avg1 == &_avg2); \
> > _avg1 + (long)(_avg2 - _avg1)/2; })
> >
> > works for the above example, but when I make it long long, so as to
> > match the longest supported type, it goes boom again - for as of yet
> > unknown reasons.
>
> I think you'd want to cast it with a (signed) instead? as in:
>
> #include <stdio.h>
>
> #define avg(x, y) ({ \
> typeof(x) _x = (x); \
> typeof(y) _y = (y); \
> (void) (&_x == &_y); \
> _x + (signed)(_y - _x)/2; })

signed is short for signed int, which is too short for say long or long
long input.

Anyway, see my previous mail in which I explained that I got the cast
order wrong.

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