Re: [uml-devel] [PATCH 5/6] slab: Annotate slab

From: Pekka Enberg
Date: Wed Sep 03 2008 - 05:27:23 EST


Hi Steve,

On Wed, Sep 3, 2008 at 8:08 AM, Steve VanDeBogart
<vandebo-lkml@xxxxxxxxxxx> wrote:
> Thank you for pointing out the location of the kmemcheck code. I looked
> around briefly but didn't find the latest version. It does seem that
> kmemcheck and Valgrind annotations want to live in the same places so it
> makes perfect sense to combine them where possible. I'm not exactly sure
> what you find so ugly about the Valgrind annotations, please elaborate.

Upper case macros and littering #ifdefs in the code. See the kmemcheck
hooks how to do it in a clean way.

On Wed, Sep 3, 2008 at 8:08 AM, Steve VanDeBogart
<vandebo-lkml@xxxxxxxxxxx> wrote:
> It is true that code above the allocator should not be touching free'd
> slab objects. However, it is also true that objects from slabs that
> have a constructor should retain their per byte un/initialized state
> through allocation and free cycles (just the semantic of slabs with
> constructors AFAICT).

Sorry for being unclear, sure, object should be marked as initialized
when they're returned from kmem_cache_alloc(). However, what I
disagree with is *where* you're marking them as initialized. Surely
they're not semantically initialized when the slabs are allocated
(although technically they are).

On Wed, Sep 3, 2008 at 8:08 AM, Steve VanDeBogart
<vandebo-lkml@xxxxxxxxxxx> wrote:
> Ideally, we'd tell Valgrind that the bytes of a free'd slab object are
> no longer accessible, but the initialized state should remain the same
> until the object is made accessible again by the next allocation of
> the object. Unfortunately, the compression method for A & V bits in
> Valgrind doesn't allow a region to be inaccessible and retain validness
> bits.

I don't see why you should mark them initialized all the time. Just
mark them as uninitialized on kmem_cache_free() and again as
initialized when they're about to be returned from kmem_cache_alloc()
like we do in kmemcheck.

Pekka
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