Re: [PATCH 1/2] tracing/function-return-tracer: Make the function return tracer lockless
From: Frédéric Weisbecker
Date: Thu Nov 13 2008 - 15:06:38 EST
2008/11/13 Ingo Molnar <mingo@xxxxxxx>:
> you are right - it needs a bit more logic.
>
> I think the simplest would be something like this:
>
> atomic64_t global_clock = INIT_ATOMIC64(0);
>
> u64 global_time()
> {
> u64 now, delta, now_global, prev_global;
>
> do {
> prev_global = atomic64_read(&global_clock);
> now = cpu_clock(raw_smp_processor_id());
>
> if ((s64)(now - prev_global) < 0) {
> now = prev_global;
> break;
> }
> } while (atomic64_cmpxchg(&global_clock,
> prev_global, now) != prev_global);
>
> return now;
> }
>
> This is the simplest way of implementing monotonic time: we only allow
> global_clock to go forwards. If all cpu_clock()s are perfectly in
> sync, we've got no problem: then "now - prev_global" will never be
> negative and we can return the local clock as the latest global time.
>
> But if one of the CPU clocks is "behind", the function returns the
> latest global time up until the local clock catches up. Time wont be
> allowed to jump around by going back. If the clock is behind for a
> long time, then we get a lot of timestamps with the same value -
Ok! I understand now this approach.
So, if global ordering flag is set, we return this kind of protected value,
and on the opposite, we return the normal cpu_clock() local value.
> Would that work? [ Would you be interested in sending patches? :-) ]
Yes :-)
> that
> will be very visible in the trace and we'll then work in improving the
> cpu_clock() implementation.
>
> So i think we could start with this simplest approach, and see how
> often we get the same timestamp for a long time (indication of the
> clocks being not perfectly in sync).
Ok, good idea.
Thanks for the explanations!
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