Re: [patch 1/7] slab: introduce kzfree()

[Hugh Dickins]

On Thu, 19 Feb 2009, Matt Mackall wrote:
> On Thu, 2009-02-19 at 16:34 +0000, Hugh Dickins wrote:
> > On Thu, 19 Feb 2009, Pekka Enberg wrote:
> > > On Thu, 2009-02-19 at 10:22 +0900, KOSAKI Motohiro wrote:
> > > > 
> > > > poisonig is transparent feature from caller.
> > > > but the caller of kzfree() know to fill memory and it should know.
> > > 
> > > Debatable, sure, but doesn't seem like a big enough reason to make
> > > kzfree() differ from kfree().
> > 
> > There may be more important things for us to worry about,
> > but I do strongly agree with KOSAKI-san on this.
> > 
> > kzfree() already differs from kfree() by a "z": that "z" says please
> > zero the buffer pointed to; "const" says it won't modify the buffer
> > pointed to.  What sense does kzfree(const void *) make?  Why is
> > keeping the declarations the same apart from the "z" desirable?
> > 
> > By all means refuse to add kzfree(), but please don't add it with const.
> > 
> > I can see that the "const" in kfree(const void *) is debatable
> > [looks to see how userspace free() is defined: without a const],
> > I can see that it might be nice to have some "goesaway" attribute
> > for such pointers instead; but I don't see how you can argue for
> > kzalloc(const void *).
    ^^^^^^^^^^^^^^^^^^^^^
(Of course I meant to say "kzfree(const void *)" there.)

> 
> This is what Linus said last time this came up:
> 
> http://lkml.org/lkml/2008/1/16/227

Thanks for that, I remember it now.

Okay, that's some justification for kfree(const void *).

But I fail to see it as a justification for kzfree(const void *):
if someone has "const char *string = kmalloc(size)" and then
wants that string zeroed before it is freed, then I think it's
quite right to cast out the const when calling kzfree().

Hugh
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