Re: [PATCH 31/34] move virtrng_remove to .devexit.text
From: Michael S. Tsirkin
Date: Thu Oct 01 2009 - 14:08:08 EST
On Thu, Oct 01, 2009 at 07:41:16PM +0200, Uwe Kleine-König wrote:
> Hello Michael,
>
> > > But note it's not an error in general to use a .text function as remove
> > > callback. E.g. take drivers/gpio/twl4030-gpio.c. gpio_twl4030_remove
> > > is used in gpio_twl4030_probe which is defined using __devinit. So
> > > using __devexit for gpio_twl4030_remove is wrong. (So there is a bug,
> > > as gpio_twl4030_remove uses __devexit.) I didn't try, but as far as I
> > > understand this will result in a compile error if the driver is built-in
> > > with HOTPLUG=n.
> >
> > Wait a second.
> > As far as I understand, __devexit makes it possible to remove code if
> > hotplug is off.
> right.
>
> > At least for static functions, it's enough to mark their only use
> > as _devexit_p, and compiler will remove the text as it's unused.
> >
> > Isn't that right?
> hmm, I don't know. I'll try, one moment. OK, you're right. The
> function is discarded with a compiler warning.
>
> > If so, what, again, was the motivation for the patches that added
> > __devexit to functions that were already used with __devexit_p?
> I thought it saves some memory, but as it looks now it only fixes a
> compiler warning.
We can redefine __devexit_p(x) to something like
#define __devexit_p(x) ((typeof(x) *)NULL)
and this will shut down the warning without need to fix the code.
Using _devexit_p for static functions is also safer
than __devexit since if you define a function as __devexit
and by mistake call it from another context, it won't link.
Makes sense?
> Note there are two types of errors fixed in this series. One is:
>
> -static int func(void arg)
> +static int __devexit func(void arg)
>
> if the only usage of func() is wraped by __devexit_p. This is (as
> seen above) not that critical, there is only a warning fixed.
>
> The other type results in a build failure:
>
> -remove = __devexit_p(another_func),
> +remove = __exit_p(another_func),
>
> with another_func being defined using __exit. In the case
> defined(MODULE) && defined(CONFIG_HOTPLUG) another_func is discarded,
> but __devexit_p(another_func) evaluates to another_func and thus the
> module doesn't link.
Yes, calling __exit function from non- __exit is always a bug.
I think there's a make flag to warn about this, not sure why it's
not the default.
> Best regards
> Uwe
>
> --
> Pengutronix e.K. | Uwe Kleine-König |
> Industrial Linux Solutions | http://www.pengutronix.de/ |
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