Re: [PATCH 1/4] jump label - make init_kernel_text() global
From: Mathieu Desnoyers
Date: Tue Oct 06 2009 - 23:24:52 EST
* Masami Hiramatsu (mhiramat@xxxxxxxxxx) wrote:
>
>
> Mathieu Desnoyers wrote:
> > * Steven Rostedt (rostedt@xxxxxxxxxxx) wrote:
> >> On Sat, 2009-10-03 at 08:39 -0400, Mathieu Desnoyers wrote:
> >>
> >>> I might be missing a bit of context here, I just want to make sure we
> >>> are on the same page: patching a jmp instruction is safe on UP, safe
> >>> with stop_machine(), is very likely safe with the breakpoint-ipi
> >>
> >> Hi Mathieu,
> >>
> >> I've been reading through these threads (both this one and the immediate
> >> one) and I'm still a bit confused. I really want to understand this in a
> >> simple way, thus make sure everyone else understands it too.
> >>
> >> >From what Arjan said here:
> >>
> >> http://lkml.org/lkml/2009/9/25/98
> >>
> >> The issue is going back from the int3 to the old value. How does the
> >> breakpoint-ipi work?
> >>
> >> Supposedly, we can add an int3 to the code without any worry. If another
> >> CPU at that same time hits that code path, it will either run the old
> >> code, or take the interrupt. The breakpoint interrupt handler, will
> >> handle that code path, and the execution continues.
> >>
> >> Now what is the issues with removing the int3 and placing back the old
> >> (or new) value. Is there an issue if another CPU is about to execute
> >> that code path as we remove the int3? If so, how does sending an IPI
> >> help the matter without adding more races?
> >>
> >> Is there only an issue if we change the old value with something else,
> >> and you just need to send the IPI after you modify the old code and
> >> before removing the int3?
> >>
> >> I may just be totally confused, which I usually am. But when I'm not
> >> confused, I feel that the code is practical ;-)
> >>
> >
> > Hi Steven,
> >
> > OK, I'll make the explanation as straightforward as possible. I'll use a
> > race example to illustrate what we try to avoid by using the
> > breakpoint+ipi scheme. After that, I present the same scenario with the
> > breakpoint+ipi in place.
> >
> > Each step shows what is executed, and what is the memory values seen by
> > the CPU. CPU A is doing the code patching, CPU B executing the code.
> > I intentionally left out some sfence required on CPU A for simplicity.)
> >
> > Initially, let's say we have:
> > (1) (2)
> > 0xeb 0xe5 (jmp to offset 0xe5)
> >
> > And we want to change this to:
> > (1) (2)
> > 0xeb 0xf0 (jmp to offset 0xf0)
> >
> > (scenario "buggy")
> >
> > CPU A | CPU B (this is about as far as my ascii-art skills go)
> > ------------------------- ;)
> > 0xeb 0xe5 0xeb 0xe5
> > 0: CPU B instruction pointer is earlier than (1)
> > CPU B pipeline speculatively predicts branches,
> > prefetches data, calculates speculated values.
> > 1: CPU B loads 0xeb
> > 2: CPU B loads 0xe5
> > 3:
> > Write to (2)
> > 0xeb 0xf0 0xeb 0xf0
> > 4: CPU B instruction pointer gets to (1), needs to validate
> > all the pipeline speculation.
> > But ! The CPU does not expect code to change underneath.
> > General protection fault (or any other fault.. random..)
> >
> >
> > Now with the breakpoint+ipi/mb() scheme:
> > (scenario A: CPU B does not hit the breakpoint)
> >
> > CPU A | CPU B
> > -------------------------
> > 0xeb 0xe5 0xeb 0xe5
> > 0: CPU B instruction pointer is earlier than (1)
> > CPU B pipeline speculatively predicts branches,
> > prefetches data, calculates speculated values.
> > 1: CPU B loads 0xeb
> > 2: CPU B loads 0xe5
> > 3:
> > Write to (1)
> > 0xcc 0xe5 0xcc 0xe5 # breakpoint inserted
> > 4: send IPI
> > 5: mfence # serializing instruction. Flushes CPU B's
> > # pipeline
> > 6:
> > Write to (2)
> > 0xcc 0xf0 0xcc 0xf0
> > 7:
> > Write to (1)
> > 0xeb 0xf0 0xeb 0xf0
> > 8: CPU B instruction pointer gets to (1), needs to validate
> > all the pipeline speculation. Because we flushed any
> > speculation prior to the mfence, we're ok.
> >
> >
> > Now, I'll show why just using the breakpoint, without IPI, is
> > problematic:
> >
> > CPU A | CPU B
> > -------------------------
> > 0xeb 0xe5 0xeb 0xe5
> > 0: CPU B instruction pointer is earlier than (1)
> > CPU B pipeline speculatively predicts branches,
> > prefetches data, calculates speculated values.
> > 1: CPU B loads 0xeb
> > 2: CPU B loads 0xe5
> > 3:
> > Write to (1)
> > 0xcc 0xe5 0xcc 0xf0 # breakpoint inserted
> > 4:
> > Write to (2)
> > 0xcc 0xf0 0xeb 0xf0 # Silly CPU B. Did not see nor use the breakpoint.
> > # Same problem as scenario "buggy".
> > 5:
> > Write to (1)
> > 0xeb 0xf0 0xeb 0xf0
> > 4: CPU B instruction pointer gets to (1), needs to validate
> > all the pipeline speculation.
> > But ! The CPU does not expect code to change underneath.
> > General protection fault (or any other fault.. random..)
> >
> > So, basically, we ensure that the only transitions CPU B will see are
> > either:
> >
> > 0xeb 0xe5 -> 0xcc 0xe5 : OK, adding breakpoint
> > 0xcc 0xe5 -> 0xcc 0xf0 : OK, not using the operand anyway, it's a
> > breakpoint!
> > 0xcc 0xf0 -> 0xeb 0xf0 : OK, removing breakpoint
> >
> > *but*, the transition we guarantee that CPU B will *never* see without
> > having a mfence executed between the old and the new version is:
> >
> > 0xeb 0xe5 -> 0xeb 0xf0 <----- buggy.
> >
> > Hope the explanation helps,
>
> Thanks for explanation.
> One thing I'd like to know is why you are using mfence
> instead of cpuid (a.k.a. sync_core()). I assume that old
> processor doesn't have mfence and is that OK?
Ah, right. Well then we can use cpuid for portability to older archs
lacking mfence.
The reason why I use mfence here is that I wanted to combine:
lfence
cpuid
into
mfence
I use a lfense on CPU B before the cpuid (and matching sfence on CPU A
between the moment I write the breakpoint instruction and the moment I
send the IPI, and another one between the moment CPU A knows the IPI has
been executed and the moment it writes the new operands).
Thanks,
Mathieu
>
> Thank you,
>
> --
> Masami Hiramatsu
>
> Software Engineer
> Hitachi Computer Products (America), Inc.
> Software Solutions Division
>
> e-mail: mhiramat@xxxxxxxxxx
>
--
Mathieu Desnoyers
OpenPGP key fingerprint: 8CD5 52C3 8E3C 4140 715F BA06 3F25 A8FE 3BAE 9A68
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