Re: Bug in scheduler when using rt_mutex

[Yong Zhang]

On Wed, Jan 19, 2011 at 1:40 PM, Mike Galbraith <efault@xxxxxx> wrote:
> On Wed, 2011-01-19 at 12:35 +0800, Yong Zhang wrote:
>
>> cfs_rq->curr != se is always true.
>
> If that were always true, we'd illegally enqueue a running task.

I'm sorry that I'm not express myself correctly.

The conclusion of (cfs_rq->curr != se is always true) is not
self-contained. IOW, it's based on one condition which is
(task_of(se) != rq->curr). So what I want to say is:
task_of(se) != rq->curr    ==>   cfs_rq_of(se)->curr != se
So,
         !running                   ==>   cfs_rq_of(se)->curr != se

Is this more clear?

Thanks,
Yong

-- 
Only stand for myself
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