Re: [PATCH 1/1] ptrace: make sure do_wait() won't hang afterPTRACE_ATTACH

From: Oleg Nesterov
Date: Sun Feb 20 2011 - 12:56:49 EST


On 02/20, Denys Vlasenko wrote:
>
> On Sunday 20 February 2011 10:40, Jan Kratochvil wrote:
> > Sure by default GDB does not do anything special, it will respawn (using
> > PTRACE_CONT(SIGSTOP)) any SIGSTOP it sees due to the default setting of:
> > (gdb) handle SIGSTOP
> > Signal Stop Print Pass to program Description
> > SIGSTOP Yes Yes Yes Stopped (signal)
> >
> > Therefore there happens the double SIGSTOP reporting as discussed before:
> > (gdb) run
> > Starting program: /bin/sleep 1h
> > # external kill -STOP <inferior pid>
> > Program received signal SIGSTOP, Stopped (signal).
> > # State: t (tracing stop)
> > (gdb) continue
> > Continuing.
> > Program received signal SIGSTOP, Stopped (signal).
> > # State: t (tracing stop)
> > (gdb) continue
> > Continuing.
> > # State: S (sleeping)
> >
> > Your proposal is I expect:
> > (gdb) run
> > Starting program: /bin/sleep 1h
> > # external kill -STOP <inferior pid>
> > Program received signal SIGSTOP, Stopped (signal).
> > # State: t (tracing stop)
> > (gdb) continue
> > Continuing.
> > # State: T (stopped)
>
> Not exactly. Even after we fix kernel so that it properly preserves
> group-stop across ptrace-stops, gdb will still see TWO
> waitpid:SIGSTOP events, not one.

Yes, I didn't notice the second report doesn't show SIGSTOP twice.
The only important change is

(gdb) continue
Continuing.
- # State: S (sleeping)
+ # State: T (stopped)


> I think you can use similar trick in gdb, so that second message says
> "Program stopped due to signal SIGSTOP, Stopped (signal)",
> not "Program received signal SIGSTOP, Stopped (signal)".

Agreed.

Oleg.

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