On 3/12/12 12:15 AM, Namhyung Kim wrote:I think it's because of the shared hist_entry. If a callchain is a
subset of another, it will be marked as inclusive so that it cannot be
contributed to total period. Say, there're two chains - X (a -> b -> c)
and Y (a -> b), once __hists__add_entry_inclusive() was called on X, we
have:
a -> b -> c
a -> b (inclusive)
a (inclusive)
And then, calling the function on Y should make:
a -> b
a (inclusive)
However, since both callchains are in tree already they'll be shared and
marked *inclusive*. Thus the total period will not increased at all for
Y. Also I guess the reverse case - add Y first, and then X - will have
the same result.
Thanks for figuring this out. Looks like using a single bit (he->inclusive) is
insufficient. How about:
struct hist_entry {
u64 period;
u64 period_self;
..
};
Normal mode: period_self == period.
Inclusive mode: period_self will be zero for inclusive hist_entries.
Shared entries: we sum up both period and period_self.
We can then compute total_period by summing up period_self.