Re: [PATCH] x86: make IDT read-only

From: Kees Cook
Date: Mon Apr 08 2013 - 19:00:12 EST


On Mon, Apr 8, 2013 at 3:56 PM, Maciej W. Rozycki <macro@xxxxxxxxxxxxxx> wrote:
> On Mon, 8 Apr 2013, Kees Cook wrote:
>
>> This makes the IDT unconditionally read-only. This primarily removes
>> the IDT from being a target for arbitrary memory write attacks. It has
>> an added benefit of also not leaking (via the "sidt" instruction) the
>> kernel base offset, if it has been relocated.
> [...]
>> --- a/arch/x86/kernel/cpu/intel.c
>> +++ b/arch/x86/kernel/cpu/intel.c
>> @@ -215,7 +201,6 @@ static void __cpuinit intel_workarounds(struct cpuinfo_x86 *c)
>>
>> c->f00f_bug = 1;
>> if (!f00f_workaround_enabled) {
>> - trap_init_f00f_bug();
>> printk(KERN_NOTICE "Intel Pentium with F0 0F bug - workaround enabled.\n");
>> f00f_workaround_enabled = 1;
>> }
>
> FWIW the change looks reasonable to me, however given that that it makes
> the arrangement unconditional and there is no longer a workaround to
> enable I think it would make sense to remove the conditional block quoted
> above altogether, along with the f00f_workaround_enabled variable itself
> (alternatively "Intel Pentium with F0 0F bug" alone could be printed
> instead and the name of the variable adjusted to make sense with the new
> meaning -- up to you to decide).

Ah, yes, I misread this and didn't see that the ifdef ended 2 lines
further down. :) I'll just remove the entire section of code.

-Kees

--
Kees Cook
Chrome OS Security
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