Re: [PATCH] fs: make sure we do not read beyond allocation
From: Richard Weinberger
Date: Fri Oct 04 2013 - 06:38:11 EST
On Fri, Oct 4, 2013 at 8:05 AM, Dmitry Vyukov <dvyukov@xxxxxxxxxx> wrote:
> On Fri, Oct 4, 2013 at 12:57 AM, Al Viro <viro@xxxxxxxxxxxxxxxxxx> wrote:
>> On Thu, Oct 03, 2013 at 12:36:08PM -0700, Kees Cook wrote:
>>> > Kees, try to think for a minute[1]. Really. We have general-purpose
>>> > ...
>>> > [1] yes, yes, I know - the mere mention of security should've prevented such
>>> > arrogant requests. It's an imperfect universe.
>>>
>>> I want to attempt to disassemble what you've communicating here:
>>>
>>> a) I'm not thinking.
>>> b) Requesting that someone think when they mention security is arrogant.
>>
>> Not really.
>>
>> It's just that all too often completely pointless changes are touted
>> as security hardening. With replies along the lines of "it doesn't
>> really buy you anything" countered with indignant "but what if
>> <impossible situation>" and/or references to "defense in depth" (used
>> as a magical incantation), etc.
>>
>> You've posted a provably pointless patch. Happens to all of us. And in
>> reply to "it's pointless for the following reasons" (with moderate
>> level of sarcasm) you responded pretty much with "but what if allocator
>> changes? It's more robust that way". OK, but if you go for that
>> kind of arguments (and they can be valid), you'd better be correct.
>> You were not, and for very obvious reasons. Let me repeat, this
>> time with sarcasm level down to zero:
>>
>> Let n be some integer between 32 and 4096 and N be equal to n rounded up
>> to word size. If kmalloc(n) returns a pointer such that fetch from
>> (char *)p[N - 1] triggers an exception, we have a badly broken kernel.
>> It can happen only if there is a page boundary between p[n-1] and p[N-1],
>> which means that p is not word-aligned.
>> Consider the following code:
>> struct foo {
>> unsigned long n;
>> char a[];
>> } *p = kmalloc(offsetof(struct foo, a) + 33);
>> if (p)
>> p->n = 1;
>> and note that it will result in an exception on any architecture that prohibits
>> unaligned accesses in the kernel. Even on architectures where those are
>> allowed, misaligned structures mean serious correctness problems (atomicity of
>> stores, etc.)
>>
>> In other words, kmalloc() (or, indeed, userland malloc()) demonstrating
>> such behaviour would need immediate fixing. The only exception I can
>> think of is something with byte granularity of memory protection; in such
>> case we can have that without unaligned return values returned by allocator.
>> Which would require a lot of changes in mm/*, at the very least, and probably
>> would violate a lot of assumptions elsewhere in the kernel (starting with
>> sizeof(void *) == sizeof(unsigned long)).
>>
>>> What the patch does help with, though, is dynamic analysis tools that
>>> are looking for out-of-bound reads, which this clearly is. It should
>>> be considered a violation of the API to attempt to access a range
>>> beyond what was requested for the allocation. Fixing this means lots
>>> of noise vanishes from such analysis of the allocation API, letting
>>> other tools besides just KASAN do work to find other more serious
>>> problems in heap usage.
>>>
>>> Does fixing this to help dynamic analysis tools somehow make the
>>> kernel worse? I think that fixing this makes it easier to find further
>>> bugs that might be much more serious.
>>
>> Possibly true. But then I'd suggest wrapping that into a different ifdef;
>> grep for ifdef __CHECKER__, with comment along the lines of "to simplify
>> analysis of potential out-of-bounds accesses".
>
>
> Hi,
>
> Any single reason to not just fix the code?
>
> With this patch:
> + sticks with "do not access beyond request size", which is a good
> thing all others equal
> + makes static and dynamic verification tools happy
> - ???
- It does not fix anything, it only shuts up the checker
- It adds another ifdef where it is not obvious why it's needed
Therefore it makes more sense to add a ifdef __CHECKER__ such that
everyone immediately knows that the issue is only false positive.
--
Thanks,
//richard
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