[PATCH 2/5] futex: Check for pi futex_q only once

[Davidlohr Bueso]

All wake_futex() callers already verify that the we are not dealing with
a pi futex_q, so we can remove the redundant WARN() check, as this is never
triggered anyway.

Cc: Ingo Molnar <mingo@xxxxxxxxxx>
Cc: Darren Hart <dvhart@xxxxxxxxxxxxxxx>
Cc: Peter Zijlstra <peterz@xxxxxxxxxxxxx>
Cc: Thomas Gleixner <tglx@xxxxxxxxxxxxx>
Cc: Mike Galbraith <efault@xxxxxx>
Cc: Jeff Mahoney <jeffm@xxxxxxxx>
Cc: Linus Torvalds <torvalds@xxxxxxxxxxxxxxxxxxxx>
Cc: Scott Norton <scott.norton@xxxxxx>
Cc: Tom Vaden <tom.vaden@xxxxxx>
Cc: Aswin Chandramouleeswaran <aswin@xxxxxx>
Cc: Waiman Long <Waiman.Long@xxxxxx>
Cc: Jason Low <jason.low2@xxxxxx>
Signed-off-by: Davidlohr Bueso <davidlohr@xxxxxx>
---
 kernel/futex.c | 3 ---
 1 file changed, 3 deletions(-)

diff --git a/kernel/futex.c b/kernel/futex.c
index e6ffe73..0768c68 100644
--- a/kernel/futex.c
+++ b/kernel/futex.c
@@ -844,9 +844,6 @@ static void wake_futex(struct futex_q *q)
 {
 	struct task_struct *p = q->task;
 
-	if (WARN(q->pi_state || q->rt_waiter, "refusing to wake PI futex\n"))
-		return;
-
 	/*
 	 * We set q->lock_ptr = NULL _before_ we wake up the task. If
 	 * a non-futex wake up happens on another CPU then the task
-- 
1.8.1.4

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