Re: [PATCH] arm: memset: zero out upper bytes in r1
From: Vladimir Murzin
Date: Thu May 08 2014 - 04:11:37 EST
Andrey Ryabinin <a.ryabinin <at> samsung.com> writes:
>
> memset doesn't work right for following example:
>
> signed char c = 0xF0;
> memset(addr, c, size);
>
> Variable c is signed, so after typcasting to int the value will be 0xFFFFFFF0.
> This value will be passed through r1 regitster to memset function.
> memset doesn't zero out upper bytes in r1, so memory will be filled
> with 0xFFFFFFF0 instead of expected 0xF0F0F0F0.
It behaves the same as a generic implementation in lib/string.c, moreover
gcc built-in behaves the same. So it looks like expected behavior and POSIX
Programmer's Manual (man 3posix memset) explicitly says that "c" is
converted to unsigned char.
Cheers
Vladimir
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