Re: sched: hang in migrate_swap
From: Peter Zijlstra
Date: Wed May 14 2014 - 06:26:35 EST
On Wed, May 14, 2014 at 02:21:04PM +0400, Kirill Tkhai wrote:
>
>
> 14.05.2014, 14:14, "Peter Zijlstra" <peterz@xxxxxxxxxxxxx>:
> > On Wed, May 14, 2014 at 01:42:32PM +0400, Kirill Tkhai wrote:
> >
> >> Peter, do we have to queue stop works orderly?
> >>
> >> Is there is not a possibility, when two pair of works queued different on
> >> different cpus?
> >>
> >> kernel/stop_machine.c | 10 ++++++++--
> >> 1 file changed, 8 insertions(+), 2 deletions(-)
> >> diff --git a/kernel/stop_machine.c b/kernel/stop_machine.c
> >> index b6b67ec..29e221b 100644
> >> --- a/kernel/stop_machine.c
> >> +++ b/kernel/stop_machine.c
> >> @@ -250,8 +250,14 @@ struct irq_cpu_stop_queue_work_info {
> >> static void irq_cpu_stop_queue_work(void *arg)
> >> {
> >> struct irq_cpu_stop_queue_work_info *info = arg;
> >> - cpu_stop_queue_work(info->cpu1, info->work1);
> >> - cpu_stop_queue_work(info->cpu2, info->work2);
> >> +
> >> + if (info->cpu1 < info->cpu2) {
> >> + cpu_stop_queue_work(info->cpu1, info->work1);
> >> + cpu_stop_queue_work(info->cpu2, info->work2);
> >> + } else {
> >> + cpu_stop_queue_work(info->cpu2, info->work2);
> >> + cpu_stop_queue_work(info->cpu1, info->work1);
> >> + }
> >> }
> >
> > I'm not sure, we already send the IPI to the first cpu of the pair, so
> > supposing we have 4 cpus, and get 4 pairs like:
> >
> > 0,1 1,2 2,3 3,0
> >
> > That would result in IPIs to 0, 1, 2, and 0 again, and since the IPI
> > function is serialized I don't immediately see a way for this to
> > deadlock.
>
> It's about stop_two_cpus(), I have a distrust about other users of stop task:
>
> queue_stop_cpus_work() queues work consequentially:
>
> 0 1 2 4
>
> stop_two_cpus() may queue:
>
> 1 0
>
> Looks like, stop thread on 0th and on 1th are waiting for wrong works.
so we serialize stop_cpus_work() vs stop_two_cpus() with an l/g lock.
Ah, but stop_cpus_work() only holds the global lock over queueing, it
doesn't wait for completion, that might indeed cause a problem.
Also, since its two different cpus queueing, the ordered queue doesn't
really matter, you can still interleave the all and two sets and get
into this state.
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