Re: [RFC PATCH 2/2 with seqcount v3] reservation: add suppport for read-only access using rcu

[Thomas Hellstrom]

On 05/19/2014 03:13 PM, Maarten Lankhorst wrote:
> op 19-05-14 15:42, Thomas Hellstrom schreef:
>> Hi, Maarten!
>>
>> Some nitpicks, and that krealloc within rcu lock still worries me.
>> Otherwise looks good.
>>
>> /Thomas
>>
>>
>>
>> On 04/23/2014 12:15 PM, Maarten Lankhorst wrote:
>>> @@ -55,8 +60,8 @@ int reservation_object_reserve_shared(struct
>>> reservation_object *obj)
>>>               kfree(obj->staged);
>>>               obj->staged = NULL;
>>>               return 0;
>>> -        }
>>> -        max = old->shared_max * 2;
>>> +        } else
>>> +            max = old->shared_max * 2;
>> Perhaps as a separate reformatting patch?
> I'll fold it in to the patch that added
> reservation_object_reserve_shared.
>>> +
>>> +int reservation_object_get_fences_rcu(struct reservation_object *obj,
>>> +                      struct fence **pfence_excl,
>>> +                      unsigned *pshared_count,
>>> +                      struct fence ***pshared)
>>> +{
>>> +    unsigned shared_count = 0;
>>> +    unsigned retry = 1;
>>> +    struct fence **shared = NULL, *fence_excl = NULL;
>>> +    int ret = 0;
>>> +
>>> +    while (retry) {
>>> +        struct reservation_object_list *fobj;
>>> +        unsigned seq;
>>> +
>>> +        seq = read_seqcount_begin(&obj->seq);
>>> +
>>> +        rcu_read_lock();
>>> +
>>> +        fobj = rcu_dereference(obj->fence);
>>> +        if (fobj) {
>>> +            struct fence **nshared;
>>> +
>>> +            shared_count = ACCESS_ONCE(fobj->shared_count);
>> ACCESS_ONCE() shouldn't be needed inside the seqlock?
> Yes it is, shared_count may be increased, leading to potential
> different sizes for krealloc and memcpy
> if the ACCESS_ONCE is removed. I could use shared_max here instead,
> which stays the same,
> but it would waste more memory.

Maarten, Another perhaps ignorant question WRT this,
Does ACCESS_ONCE() guarantee that the value accessed is read atomically?

/Thomas
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