Re: [PATCH 2/4] watchdog: imgpdc: Intialize timeout to default value

[Guenter Roeck]

On 03/31/2015 11:49 AM, Andrew Bresticker wrote:
> From: Naidu Tellapati <naidu.tellapati@xxxxxxxxxx>
>
> Currently the watchdog timeout is initialized to 0.  Initialize it to
> its default value instead.
>
> Signed-off-by: Naidu Tellapati <naidu.tellapati@xxxxxxxxxx>
> Signed-off-by: Andrew Bresticker <abrestic@xxxxxxxxxxxx>
> Cc: Ezequiel Garcia <ezequiel.garcia@xxxxxxxxxx>
> ---
>   drivers/watchdog/imgpdc_wdt.c | 2 +-
>   1 file changed, 1 insertion(+), 1 deletion(-)
>
> diff --git a/drivers/watchdog/imgpdc_wdt.c b/drivers/watchdog/imgpdc_wdt.c
> index c4151cd..f3f65ac 100644
> --- a/drivers/watchdog/imgpdc_wdt.c
> +++ b/drivers/watchdog/imgpdc_wdt.c
> @@ -42,7 +42,7 @@
>   #define PDC_WDT_MIN_TIMEOUT		1
>   #define PDC_WDT_DEF_TIMEOUT		64
>
> -static int heartbeat;
> +static int heartbeat = PDC_WDT_DEF_TIMEOUT;
>   module_param(heartbeat, int, 0);
>   MODULE_PARM_DESC(heartbeat, "Watchdog heartbeats in seconds. "
>   	"(default = " __MODULE_STRING(PDC_WDT_DEF_TIMEOUT) ")");

The idea with watchdog_init_timeout() is that it can take the
timeout from devicetree unless the module parameter is provided.
By pre-initializing the module parameter, you defeat that and
make watchdog_init_timeout more or less a no-op. You might as well
set pdc_wdt->wdt_dev.timeout directly and not call watchdog_init_timeout
at all if that is what you want.

The "expected" solution would be to pre-initialize pdc_wdt->wdt_dev.timeout
but leave the module parameter alone.

Guenter

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