RE: [PATCH] net: tcp: Fix a PTO timing granularity issue

[David Laight]

From: Of Ido Yariv
> Sent: 26 May 2015 21:17
> The Tail Loss Probe RFC specifies that the PTO value should be set to
> max(2 * SRTT, 10ms), where SRTT is the smoothed round-trip time.
> 
> The PTO value is converted to jiffies, so the timer may expire
> prematurely.
> 
> This is especially problematic on systems in which HZ <= 100, so work
> around this by setting the timeout to at least 2 jiffies on such
> systems.
> 
> The 10ms figure was originally selected based on tests performed with
> the current implementation and HZ = 1000. Thus, leave the behavior on
> systems with HZ > 100 unchanged.
> 
> Signed-off-by: Ido Yariv <idox.yariv@xxxxxxxxx>
> ---
>  net/ipv4/tcp_output.c | 3 +++
>  1 file changed, 3 insertions(+)
> 
> diff --git a/net/ipv4/tcp_output.c b/net/ipv4/tcp_output.c
> index 534e5fd..5321df8 100644
> --- a/net/ipv4/tcp_output.c
> +++ b/net/ipv4/tcp_output.c
> @@ -2208,6 +2208,9 @@ bool tcp_schedule_loss_probe(struct sock *sk)
>  		timeout = max_t(u32, timeout,
>  				(rtt + (rtt >> 1) + TCP_DELACK_MAX));
>  	timeout = max_t(u32, timeout, msecs_to_jiffies(10));
> +#if HZ <= 100
> +	timeout = max_t(u32, timeout, 2);
> +#endif

Why not:
	timeout = max_t(u32, timeout, max_t(u32, 2, msecs_to_jiffies(10)));
I think the RH max_t() is a compile time constant.

You need 2 jiffies to guarantee a non-zero timeout.
Even if HZ=199 with a 'rounding down' msecs_to_jiffies() you get 1 jiffy
and a possible immediate timeout.

There are probably other places where msecs_to_jiffies() better not return 1.

	David

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