Re: [PATCH] NVMe: Fixed race between nvme_thread & probe path.
From: Parav Pandit
Date: Thu Jun 18 2015 - 13:48:53 EST
On Thu, Jun 18, 2015 at 9:29 PM, Jon Derrick <jonathan.derrick@xxxxxxxxx> wrote:
> On Thu, Jun 18, 2015 at 04:13:50PM +0530, Parav Pandit wrote:
>> Kernel thread nvme_thread and driver load process can be executing
>> in parallel on different CPU. This leads to race condition whenever
>> nvme_alloc_queue() instructions are executed out of order that can
>> reflects incorrect value for nvme_thread.
>> Memory barrier in nvme_alloc_queue() ensures that it maintains the
>> order and and data dependency read barrier in reader thread ensures
>> that cpu cache is synced.
>>
>> Signed-off-by: Parav Pandit <Parav.pandit@xxxxxxxxxxxxx>
>> ---
>> drivers/block/nvme-core.c | 12 ++++++++++--
>> 1 files changed, 10 insertions(+), 2 deletions(-)
>>
>> diff --git a/drivers/block/nvme-core.c b/drivers/block/nvme-core.c
>> index 5961ed7..90fb0ce 100644
>> --- a/drivers/block/nvme-core.c
>> +++ b/drivers/block/nvme-core.c
>> @@ -1403,8 +1403,10 @@ static struct nvme_queue *nvme_alloc_queue(struct nvme_dev *dev, int qid,
>> nvmeq->q_db = &dev->dbs[qid * 2 * dev->db_stride];
>> nvmeq->q_depth = depth;
>> nvmeq->qid = qid;
>> - dev->queue_count++;
>> dev->queues[qid] = nvmeq;
>> + /* update queues first before updating queue_count */
>> + smp_wmb();
>> + dev->queue_count++;
>>
>> return nvmeq;
>>
>
> This has been applied already as an explicit mb()
Since these structure is only accessible by software, won't smp_wmb()
sufficient enough?
>
>> @@ -2073,7 +2075,13 @@ static int nvme_kthread(void *data)
>> continue;
>> }
>> for (i = 0; i < dev->queue_count; i++) {
>> - struct nvme_queue *nvmeq = dev->queues[i];
>> + struct nvme_queue *nvmeq;
>> +
>> + /* make sure to read queue_count before
>> + * traversing queues.
>> + */
>> + smp_read_barrier_depends();
>> + nvmeq = dev->queues[i];
>> if (!nvmeq)
>> continue;
>> spin_lock_irq(&nvmeq->q_lock);
>
> I don't think this is necessary. If queue_count is incremented while in this loop, it will be picked up the next time the kthread runs
ok. Make sense.
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