Re: [PATCH] x86: Fix detection of GCC -mpreferred-stack-boundary support

From: Andy Lutomirski
Date: Mon Jul 06 2015 - 13:59:46 EST


On Mon, Jul 6, 2015 at 10:40 AM, Ingo Molnar <mingo@xxxxxxxxxx> wrote:
>
> * Andy Lutomirski <luto@xxxxxxxxxxxxxx> wrote:
>
>> > My reasoning: on modern uarchs there's no penalty for 32-bit misalignment of
>> > 64-bit variables, only if they cross 64-byte cache lines, which should be rare
>> > with a chance of 1:16. This small penalty (of at most +1 cycle in some
>> > circumstances IIRC) should be more than counterbalanced by the compression of
>> > the stack by 5% on average.
>>
>> I'll counter with: what's the benefit? There are no operations that will
>> naturally change RSP by anything that isn't a multiple of 8 (there's no pushl in
>> 64-bit mode, or at least not on AMD chips -- the Intel manual is a bit vague on
>> this point), so we'll end up with RSP being a multiple of 8 regardless. Even if
>> we somehow shaved 4 bytes off in asm, that still wouldn't buy us anything, as a
>> dangling 4 bytes at the bottom of the stack isn't useful for anything.
>
> Yeah, so it might be utilized in frame-pointer less builds (which we might be able
> to utilize in the future if sane Dwarf code comes around), which does not use
> push/pop to manage the stack but often has patterns like:
>
> ffffffff8102aa90 <SyS_getpriority>:
> ffffffff8102aa90: 48 83 ec 18 sub $0x18,%rsp
>
> and uses MOVs to manage the stack. Those kinds of stack frames could be 4-byte
> granular as well.
>
> But yeah ... it's pretty marginal.

To get even that, we'd need an additional ABI-changing GCC flag to
change GCC's idea of the alignment of long from 8 to 4. (I just
checked: g++ thinks that alignof(long) == 8. I was too lazy to look
up how to ask the equivalent question in C.)

--Andy
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