RE: [PATCH V2 1/1] perf/x86: Add Intel power cstate PMUs support
From: Liang, Kan
Date: Thu Aug 06 2015 - 17:45:45 EST
> -----Original Message-----
> From: Stephane Eranian [mailto:eranian@xxxxxxxxxx]
> Sent: Thursday, August 06, 2015 4:38 PM
> To: Liang, Kan
> Cc: Peter Zijlstra; mingo@xxxxxxxxxx; Arnaldo Carvalho de Melo;
> ak@xxxxxxxxxxxxxxx; LKML
> Subject: Re: [PATCH V2 1/1] perf/x86: Add Intel power cstate PMUs
> support
>
> On Thu, Aug 6, 2015 at 1:25 PM, Liang, Kan <kan.liang@xxxxxxxxx> wrote:
> >
> >> >> >> >> +static cpumask_t power_cstate_core_cpu_mask;
> >> >> >> >
> >> >> >> > That one typically does not need a cpumask.
> >> >> >> >
> >> >> >> You need to pick one CPU out of the multi-core. But it is for
> >> >> >> client parts thus there is only one socket. At least this is my
> >> understanding.
> >> >> >>
> >> >> >
> >> >> > CORE_C*_RESIDENCY are available for physical processor core.
> >> >> > So logical processor in same physical processor core share the
> >> >> > same counter.
> >> >> > I think we need the cpumask to identify the default logical
> >> >> > processor which do counting.
> >> >> >
> >> >> Did you restrict these events to system-wide mode only?
> >> >>
> >> Ok, so that means that your cpumask includes one HT per physical core.
> >> But then, the result is not the simple aggregation of all the N/2 CPUs.
> >
> > The counter counts per physical core. The result is the aggregation of
> > all HT cpus in same physical core.
>
> But then don't you need to divide by 2 to get a meaningful result?
Rethink of it. I think I was unclear about the aggregation of all HT cpus
in same physical core.
physical core Cstate should equal to min(logical core C-state).
So only all logical core enters C6-state, the physical core enters C6-state,
then CORE_C6_RESIDENCY counts.
So if we only count on one logical core/HT for CORE_C6_RESIDENCY.
We don't need to divide by 2. The count result is the residency when all logical
core in C6 (some may deeper).
Thanks,
Kan