Re: [PATCH 1/2] unshare: Unsharing a thread does not require unsharing a vm
From: Oleg Nesterov
Date: Thu Aug 13 2015 - 08:58:13 EST
Let me first say that CLONE_SIGHAND must die, I think ;) and perhaps
even sighand_struct... I am wondering if we can add something like
if ((clone_flags & (CLONE_THREAD | CLONE_SIGHAND)) == CLONE_SIGHAND)
pr_info("You are crazy, please report this to lkml\n");
into copy_process().
On 08/12, Eric W. Biederman wrote:
>
> Oleg Nesterov <oleg@xxxxxxxxxx> writes:
>
> > On 08/11, Eric W. Biederman wrote:
> >> if (unshare_flags & (CLONE_THREAD | CLONE_SIGHAND | CLONE_VM)) {
> >> - /* FIXME: get_task_mm() increments ->mm_users */
> >> - if (atomic_read(¤t->mm->mm_users) > 1)
> >> + if (!thread_group_empty(current))
> >> + return -EINVAL;
> >> + }
> >> + if (unshare_flags & CLONE_VM) {
> >> + if (!current_is_single_threaded())
> >> return -EINVAL;
> >> }
> >
> > OK, but then you can remove "| CLONE_VM" from the previous check...
>
> As an optimization, but I don't think anything cares enough for the
> optimization to be worth the confusion.
current_is_single_threaded() checks task->signal->live at the start,
so there is no optimization. But I won't argue, this doesn't hurt.
> >> /*
> >> + * If unsharing a signal handlers, must also unshare the signal queues.
> >> + */
> >> + if (unshare_flags & CLONE_SIGHAND)
> >> + unshare_flags |= CLONE_THREAD;
> >
> > This looks unnecessary, check_unshare_flags() checks "THREAD | SIGHAND".
> > And to me the comment looks misleading although I won't argue.
>
> I absolutely can not understand this code if we jump 5 steps ahead
> and optimize out the individual dependencies, and try for a flattened
> dependency tree instead. I can validate the individual dependencies
> from first principles.
>
> If we jump several steps ahead I can not validate the individual
> dependencies.
OK,
> > And in fact this doesn't look exactly right, or I am totally confused.
> > Shouldn't we do
> >
> > if (unshare_flags & CLONE_SIGHAND)
> > unshare_flags |= CLONE_VM;
>
> Nope. The backward definitions of the flags in unshare has gotten you.
See below,
> CLONE_SIGHAND means that you want a struct sighand_struct with a count
> of 1.
This is (almost) true,
> Nothing about a sighand_struct with a count of 1 implies or
> requires mm_users == 1. clone can quite happily create those.
See
if ((clone_flags & CLONE_SIGHAND) && !(clone_flags & CLONE_VM))
in copy_process(). So if you have a shared sighand_struct, your ->mm
is also shared, current_is_single_threaded() will notice this.
> > Otherwise suppose that a single threaded process does clone(VM | SIGHAND)
> > and (say) child does sys_unshare(SIGHAND). This will wrongly succeed
> > afaics.
>
> Why would it be wrong to succeed in that case? struct sighand_struct
> has a count of 1.
How that? clone(VM | SIGHAND) will share ->sighand and increment its
count.
> unshare(CLONE_SIGHAND) requests a sighand_struct with
> a count of 1.
Exactly, that is why it is wrong to succeed.
> unshare(SIGHAND) needs to guarantee that when it returns sighand->count == 1.
> So unshare(SIGHAND) needs to test for sighand->count == 1.
Oh, I do not think we should check sighand->count. This can lead to
the same problem we have with the current current->mm->mm_users check.
Most probably today nobody increments sighand->count (I didn't even
try to verify). But this is possible, and I saw the code which did
this to pin ->sighand...
Oleg.
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