Re: [BUG/RFC] perf test fails on AMD CPUs

[Borislav Petkov]

On Mon, Aug 17, 2015 at 09:06:59AM -0700, Andy Lutomirski wrote:
> >> expected course of actions is:
> >>   1) CPU hits 'test_function'
> >>   2) DB exception is triggered, with RFLAGS.RF=0
> >>   3) DB exception handler sets regs->RFLAGS.RF=1 and perf handler
> >>      triggers irq_work pending work
> >>   4) DB exception executes iretd
> >>   5) irq_work interrupt is triggered, with RFLAGS.RF=1
> >>   6) irq_work interrupt calls kill_fasync with SIGIO signal
> >>   7) irq_work interrupt on return to userspace calls prepare_exit_to_usermode
> >>      which actually delivers the SIGIO signal
> >>   8) sigreturn syscall prepare registers to return to the
> >>      instruction from step 1) and sets RFLAGS.RF to the its original
> >>      value from step 5) (RFLAGS.RF=1)
> >>   9) CPU hits 'test_function' and DB exception is NOT triggered
> >>      due to RFLAGS.RF=1
> >>
> >> this is how I see it works on Intel
> >>
> >> But AMD gives me RFLAGS.RF=0 on step 5, which makes the step 9 to
> >> trigger the DB exception once again and makes the test fail.

Waaaiit a minute!

APM says #DB exception handler must set RF in the EFLAGS image on the
exception stack (or whereever it is running) so that the breakpoint
doesn't trigger again.

Now: do_debug() *doesn't* do that but hw_breakpoint_handler() does. So
do we call hw_breakpoint_handler() in those steps above?

Because if we don't, that could explain the issue...

> > Adding Andy, he might have an idea. Leaving in the rest for reference.
> 
> Gee thanks :-p

For what, adding you to CC or leaving in the rest? :-P

> Jiri, did you instrument the code and observe do_IRQ sees RF clear in
> its pt_regs?  Also, it might be worth checking that regs->ip in the
> irq_work matches regs->ip.

Hohumm.

> It's *possible* that I messed up and broke RF restore with
> opportunistic sysret, but the code looks correct:
> 
>         testq   $(X86_EFLAGS_RF|X86_EFLAGS_TF), %r11
>         jnz     opportunistic_sysret_failed

Yeah, I was looking at that too.

> >> An IRET that sets the RF bit.
> >> JMP, CALL, or INTn through a task gate.
> >> In both of the above cases, RF is not cleared to 0 until the next instruction successfully executes.
> >> When an exception occurs (or when a string instruction is interrupted), the processor normally sets
> >> RF=1 in the RFLAGS image saved on the interrupt stack. However, when a #DB exception occurs as a
> >> result of an instruction breakpoint, the processor clears the RF bit to 0 in the interrupt-stack RFLAGS
> >> image.
> 
> That's a little weird, I think.  Shouldn't RF be zero on #DB due to a
> *watchpoint* so that a watchpoint followed immediately by a breakpoint
> works?

What is a watchpoint? R/Wn bit = 1?

Btw, that sounds weird - why would the #DB exception clear RF just so
that the #DB handler to set it right after... I'm probably missing
something obvious.

> >> â For other cases, the value pushed for RF is the value that was in EFLAG.RF at the time the event handler was
> >> called. This includes:
> >> â Debug exceptions generated in response to instruction breakpoints
> >> â Hardware-generated interrupts arriving between instructions (including those arriving after the last
> >> iteration of a repeated string instruction)
> 
> This appears to be why it works on Intel.  Does AMD not do that?  We
> could probably work around this in software (by not using irq work for
> this), but yuck.

See above.

-- 
Regards/Gruss,
    Boris.

ECO tip #101: Trim your mails when you reply.

SUSE Linux GmbH, GF: Felix ImendÃrffer, Jane Smithard, Graham Norton, HRB 21284 (AG NÃrnberg)
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