Re: [RFC 1/3] oom, sysrq: Skip over oom victims and killed tasks

From: Michal Hocko
Date: Wed Jan 13 2016 - 04:30:56 EST


On Tue 12-01-16 16:41:50, David Rientjes wrote:
> On Tue, 12 Jan 2016, Michal Hocko wrote:
>
> > diff --git a/mm/oom_kill.c b/mm/oom_kill.c
> > index abefeeb42504..2b9dc5129a89 100644
> > --- a/mm/oom_kill.c
> > +++ b/mm/oom_kill.c
> > @@ -326,6 +326,17 @@ static struct task_struct *select_bad_process(struct oom_control *oc,
> > case OOM_SCAN_OK:
> > break;
> > };
> > +
> > + /*
> > + * If we are doing sysrq+f then it doesn't make any sense to
> > + * check OOM victim or killed task because it might be stuck
> > + * and unable to terminate while the forced OOM might be the
> > + * only option left to get the system back to work.
> > + */
> > + if (is_sysrq_oom(oc) && (test_tsk_thread_flag(p, TIF_MEMDIE) ||
> > + fatal_signal_pending(p)))
> > + continue;
> > +
> > points = oom_badness(p, NULL, oc->nodemask, totalpages);
> > if (!points || points < chosen_points)
> > continue;
>
> I think you can make a case for testing TIF_MEMDIE here since there is no
> chance of a panic from the sysrq trigger. However, I'm not convinced that
> checking fatal_signal_pending() is appropriate.

My thinking was that such a process would get TIF_MEMDIE if it hits the
OOM from the allocator.

> I think it would be
> better for sysrq+f to first select a process with fatal_signal_pending()
> set so it silently gets access to memory reserves and then a second
> sysrq+f to choose a different process, if necessary, because of
> TIF_MEMDIE.

The disadvantage of this approach is that sysrq+f might silently be
ignored and the administrator doesn't have any signal about that. IMHO
sysrq+f would be much better defined if it _always_ selected and killed
a task. After all it is an explicit administrator action.
--
Michal Hocko
SUSE Labs