RE: [PATCH] ld-version: fix it on Fedora

From: Daniel Sanders
Date: Mon Jan 25 2016 - 05:49:51 EST


> From: Alexander Kapshuk [alexander.kapshuk@xxxxxxxxx]
> Sent: 23 January 2016 14:41
> To: Daniel Sanders
> Cc: James Hogan; Michael S. Tsirkin; LKML; Michal Marek; linux-kbuild@xxxxxxxxxxxxxxx; Linux MIPS Mailing List; Ralf Baechle
> Subject: Re: [PATCH] ld-version: fix it on Fedora
>
> On Wed, Jan 13, 2016 at 7:30 PM, Daniel Sanders <Daniel.Sanders@xxxxxxxxxx<mailto:Daniel.Sanders@xxxxxxxxxx>> wrote:
> Hi,
>
> The version number that's giving me problems is 2.24.51.20140217 which ld-version.sh converts to 2036931700 (20000000+2400000+510000+2014021700).
>
> At the moment, I'm wondering whether we really need to handle more than three version number components. Another thought is that the comparison could be inside ld-version.sh (or a replacement) so that it can compare the array of version components directly instead of using a constructed integer as a proxy.
>
> > -----Original Message-----
> > From: james@xxxxxxxxxxxxx<mailto:james@xxxxxxxxxxxxx> [mailto:james@xxxxxxxxxxxxx<mailto:james@xxxxxxxxxxxxx>] On Behalf Of
> > James Hogan
> > Sent: 13 January 2016 17:06
> > To: Michael S. Tsirkin
> > Cc: LKML; Michal Marek; linux-kbuild@xxxxxxxxxxxxxxx<mailto:linux-kbuild@xxxxxxxxxxxxxxx>; Linux MIPS Mailing
> > List; Ralf Baechle; Daniel Sanders
> > Subject: Re: [PATCH] ld-version: fix it on Fedora
> >
> > Cc'ing Daniel, who has hit further breakage due to unusual version numbers.
> >
> > On 7 January 2016 at 17:55, Michael S. Tsirkin <mst@xxxxxxxxxx<mailto:mst@xxxxxxxxxx>> wrote:
> > > On Fedora 23, ld --version outputs:
> > > GNU ld version 2.25-15.fc23
> > >
> > > But ld-version.sh fails to parse this, so e.g. mips build fails to
> > > enable VDSO, printing a warning that binutils >= 2.24 is required.
> > >
> > > To fix, teach ld-version to parse this format.
> > >
> > > Signed-off-by: Michael S. Tsirkin <mst@xxxxxxxxxx<mailto:mst@xxxxxxxxxx>>
> > > ---
> > >
> > > Which tree should this be merged through? Mine? MIPS?
> > >
> > > scripts/ld-version.sh | 2 ++
> > > 1 file changed, 2 insertions(+)
> > >
> > > diff --git a/scripts/ld-version.sh b/scripts/ld-version.sh
> > > index 198580d..25d23c8 100755
> > > --- a/scripts/ld-version.sh
> > > +++ b/scripts/ld-version.sh
> > > @@ -2,6 +2,8 @@
> > > # extract linker version number from stdin and turn into single number
> > > {
> > > gsub(".*)", "");
> > > + gsub(".*version ", "");
> > > + gsub("-.*", "");
> > > split($1,a, ".");
> > > print a[1]*10000000 + a[2]*100000 + a[3]*10000 + a[4]*100 + a[5];
> > > exit
> > > --
> > > MST
> > >
>
> Is this the output you're looking for?
>
> % echo 'GNU ld version 2.25-15.fc23' |
> > awk '/[0-9]+([.]?[0-9]+)+/ && !/not found$/{
> > match($0, /[0-9]+([.]?[0-9]+)+/)
> > bin=substr($0,RSTART,RLENGTH)
> > split(bin, a, ".")
> > print a[1]*10000000 + a[2]*100000 + a[3]*10000}'
> 22500000
>
> % echo 2.25.1.20140217 |
> > awk '/[0-9]+([.]?[0-9]+)+/ && !/not found$/{
> > match($0, /[0-9]+([.]?[0-9]+)+/)
> > bin=substr($0,RSTART,RLENGTH)
> > split(bin, a, ".")
> > print a[1]*10000000 + a[2]*100000 + a[3]*10000}'
> 22510000
>
> awk parsing code taken from ver_linux:
> /usr/src/linux/scripts/ver_linux:28,33
> ld -v 2>&1 |
> awk '/[0-9]+([.]?[0-9]+)+/ && !/not found$/{
> match($0, /[0-9]+([.]?[0-9]+)+/)
> printf("Binutils\t\t%s\n",
> substr($0,RSTART,RLENGTH))
> }'
>

It's close. That code doesn't quite work for my version number because the third component has two
digits and overflows into the second component in the proxy integer:
$ echo 2.24.51.20140217 |
> awk '/[0-9]+([.]?[0-9]+)+/ && !/not found$/{
> match($0, /[0-9]+([.]?[0-9]+)+/)
> bin=substr($0,RSTART,RLENGTH)
> split(bin, a, ".")
> print a[1]*10000000 + a[2]*100000 + a[3]*10000}'
22910000

but adding a zero to the first two scale factors, or removing one from the third works for me.
$ echo 2.24.51.20140217 | awk '/[0-9]+([.]?[0-9]+)+/ && !/not found$/{
> match($0, /[0-9]+([.]?[0-9]+)+/)
> bin=substr($0,RSTART,RLENGTH)
> split(bin, a, ".")
> print a[1]*100000000 + a[2]*1000000 + a[3]*10000}'
224510000
$ echo 2.24.51.20140217 | awk '/[0-9]+([.]?[0-9]+)+/ && !/not found$/{
> match($0, /[0-9]+([.]?[0-9]+)+/)
> bin=substr($0,RSTART,RLENGTH)
> split(bin, a, ".")
> print a[1]*10000000 + a[2]*100000 + a[3]*1000}'
22451000