Re: [PATCH] x86/entry: Improve system call entry comments

[Andy Lutomirski]

On Mar 8, 2016 2:27 AM, "Ingo Molnar" <mingo@xxxxxxxxxx> wrote:
>
>
> * Andy Lutomirski <luto@xxxxxxxxxxxxxx> wrote:
>
> > > >  ENTRY(entry_INT80_32)
> > >
> > > entry_INT80_32() is only used on pure 32-bit kernels, 64-bit kernels use
> > > entry_INT80_compat(). So the above text should not talk about 64-bit programs, as
> > > they can never trigger this specific entry point, right?
> > >
> >
> > 64-bit programs can and sometimes do trigger this entry point. [...]
>
> How can 64-bit programs trigger entry_INT80_32? It's only ever set on 32-bit
> kernels:
>
> #ifdef CONFIG_X86_32
>         set_system_trap_gate(IA32_SYSCALL_VECTOR, entry_INT80_32);
>         set_bit(IA32_SYSCALL_VECTOR, used_vectors);
> #endif
>
> > [...]  It does a 32-bit syscall regardless of the caller's bitness, but it
> > returns back to the caller's original context, whatever it was.
>
> That's true of INT $0x80, but I'm talking about the entry point: AFAICS
> entry_INT80_32 can only ever execute on 32-bit kernels.

Oh, duh.

>
> We don't even build the entry_32.S::entry_INT80_32 entry point on 64-bit kernels:
>
> obj-y                           := entry_$(BITS).o [...]
>
> >
> > > So I'd change the explanation to something like:
> > >
> > > > + * This entry point is active on 32-bit kernels and can thus be used by 32-bit
> > > > + * programs to perform 32-bit system calls. (Programs running on 64-bit
> > > > + * kernels executing INT $0x80 will land on another entry point:
> > > > + * entry_INT80_compat. The ABI is identical.)
> >
> > I like the part in parentheses.
>
> So the part in parentheses conflict with your above statement :)
>
> What I wanted to say with this:
>
> > > > + * This entry point is active on 32-bit kernels and can thus be used by 32-bit
> > > > + * programs to perform 32-bit system calls. (Programs running on 64-bit
> > > > + * kernels executing INT $0x80 will land on another entry point:
> > > > + * entry_INT80_compat. The ABI is identical.)
>
> ... is what it says: that entry_INT80_32 is only active on 32-bit kernels, running
> 32-bit programs, performing 32-bit system calls.
>
> Programs running on 64-bit kernels can use INT $0x80 as well, but will land on
> another, different, 64-bit kernel specific entry point.
>
> What am I missing?
>

Nothing.  I mis-read your earlier email.  Want to fix and apply it, or
should I send a new version?

> Thanks,
>
>         Ingo