Re: [RFC][PATCH 6/8] sched/rtmutex: Refactor rt_mutex_setprio()

[Juri Lelli]

Hi,

still digesting this change, but I'll point out below why I think you
are hitting a NULL ptr dereference (discussed on IRC).

On 07/06/16 21:56, Peter Zijlstra wrote:
> With the introduction of SCHED_DEADLINE the whole notion that priority
> is a single number is gone, therefore the @prio argument to
> rt_mutex_setprio() doesn't make sense anymore.
> 
> So rework the code to pass a pi_task instead.
> 
> Note this also fixes a problem with pi_top_task caching; previously we
> would not set the pointer (call rt_mutex_update_top_task) if the
> priority didn't change, this could lead to a stale pointer.
> 
> As for the XXX, I think its fine to use pi_task->prio, because if it
> differs from waiter->prio, a PI chain update is immenent.
> 
> Signed-off-by: Peter Zijlstra (Intel) <peterz@xxxxxxxxxxxxx>
> ---
>  include/linux/sched/rt.h        |   21 +-------
>  kernel/locking/rtmutex.c        |  105 +++++++++++-----------------------------
>  kernel/locking/rtmutex_common.h |    1 
>  kernel/sched/core.c             |   66 ++++++++++++++++++++-----
>  4 files changed, 88 insertions(+), 105 deletions(-)
> 

[...]

> --- a/kernel/locking/rtmutex.c
> +++ b/kernel/locking/rtmutex.c
> @@ -256,61 +256,16 @@ rt_mutex_dequeue_pi(struct task_struct *
>  	RB_CLEAR_NODE(&waiter->pi_tree_entry);
>  }
>  
> -void rt_mutex_update_top_task(struct task_struct *p)
> +static void rt_mutex_adjust_prio(struct task_struct *p)
>  {
> -	if (!task_has_pi_waiters(p)) {
> -		p->pi_top_task = NULL;
> -		return;
> -	}
> +	struct task_struct *pi_task = NULL;
>  
> -	p->pi_top_task = task_top_pi_waiter(p)->task;
> -}
> -
> -/*
> - * Calculate task priority from the waiter tree priority
> - *
> - * Return task->normal_prio when the waiter tree is empty or when
> - * the waiter is not allowed to do priority boosting
> - */
> -int rt_mutex_getprio(struct task_struct *task)
> -{
> -	if (likely(!task_has_pi_waiters(task)))
> -		return task->normal_prio;
> +	lockdep_assert_held(&p->pi_lock);
>  
> -	return min(task_top_pi_waiter(task)->prio,
> -		   task->normal_prio);
> -}
> +	if (!task_has_pi_waiters(p))

Shouldn't this be the other way around?

 if (task_has_pi_waiters(p))
 	pi_task = ...

Best,

- Juri