Re: [RFC][PATCH 1/3] locking/mutex: Rework mutex::owner

From: Will Deacon
Date: Wed Aug 24 2016 - 05:57:39 EST


On Tue, Aug 23, 2016 at 02:46:18PM +0200, Peter Zijlstra wrote:
> There's a number of iffy in mutex because mutex::count and
> mutex::owner are two different fields; this too is the reason
> MUTEX_SPIN_ON_OWNER and DEBUG_MUTEX are mutually exclusive.
>
> Cure this by folding them into a single atomic_long_t field.
>
> This nessecairly kills all the architecture specific mutex code.
>
> Signed-off-by: Peter Zijlstra (Intel) <peterz@xxxxxxxxxxxxx>

[...]

> void __sched mutex_unlock(struct mutex *lock)
> {
> - /*
> - * The unlocking fastpath is the 0->1 transition from 'locked'
> - * into 'unlocked' state:
> - */
> -#ifndef CONFIG_DEBUG_MUTEXES
> - /*
> - * When debugging is enabled we must not clear the owner before time,
> - * the slow path will always be taken, and that clears the owner field
> - * after verifying that it was indeed current.
> - */
> - mutex_clear_owner(lock);
> + unsigned long owner;
> +
> +#ifdef CONFIG_DEBUG_MUTEXES
> + DEBUG_LOCKS_WARN_ON(__mutex_owner(lock) != current);
> #endif
> - __mutex_fastpath_unlock(&lock->count, __mutex_unlock_slowpath);
> -}
>
> + owner = atomic_long_read(&lock->owner);
> + for (;;) {
> + unsigned long old;
> +
> + old = atomic_long_cmpxchg_release(&lock->owner, owner, owner & 0x03);
> + if (old == owner)
> + break;
> +
> + owner = old;
> + }

Can you rewrite this using atomic_long_fetch_and_release?

Will