[PATCH 1/2 v2] sched: fix find_idlest_group for fork

[Vincent Guittot]

During fork, the utilization of a task is init once the rq has been
selected because the current utilization level of the rq is used to set
the utilization of the fork task. As the task's utilization is still
null at this step of the fork sequence, it doesn't make sense to look for
some spare capacity that can fit the task's utilization.
Furthermore, I can see perf regressions for the test "hackbench -P -g 1"
because the least loaded policy is always bypassed and tasks are not
spread during fork.

With this patch and the fix below, we are back to same performances as
for v4.8. The fix below is only a temporary one used for the test until a
smarter solution is found because we can't simply remove the test which is
useful for others benchmarks

@@ -5708,13 +5708,6 @@ static int select_idle_cpu(struct task_struct *p, struct sched_domain *sd, int t
 
 	avg_cost = this_sd->avg_scan_cost;
 
-	/*
-	 * Due to large variance we need a large fuzz factor; hackbench in
-	 * particularly is sensitive here.
-	 */
-	if ((avg_idle / 512) < avg_cost)
-		return -1;
-
 	time = local_clock();
 
 	for_each_cpu_wrap(cpu, sched_domain_span(sd), target, wrap) {

Signed-off-by: Vincent Guittot <vincent.guittot@xxxxxxxxxx>
---
 kernel/sched/fair.c | 6 ++++++
 1 file changed, 6 insertions(+)

diff --git a/kernel/sched/fair.c b/kernel/sched/fair.c
index aa47589..820a787 100644
--- a/kernel/sched/fair.c
+++ b/kernel/sched/fair.c
@@ -5463,13 +5463,19 @@ find_idlest_group(struct sched_domain *sd, struct task_struct *p,
 	 * utilized systems if we require spare_capacity > task_util(p),
 	 * so we allow for some task stuffing by using
 	 * spare_capacity > task_util(p)/2.
+	 * spare capacity can't be used for fork because the utilization has
+	 * not been set yet as it need to get a rq to init the utilization
 	 */
+	if (sd_flag & SD_BALANCE_FORK)
+		goto no_spare;
+
 	if (this_spare > task_util(p) / 2 &&
 	    imbalance*this_spare > 100*most_spare)
 		return NULL;
 	else if (most_spare > task_util(p) / 2)
 		return most_spare_sg;
 
+no_spare:
 	if (!idlest || 100*this_load < imbalance*min_load)
 		return NULL;
 	return idlest;
-- 
2.7.4