Re: [PATCH RFC 10/14] block, bfq: add Early Queue Merge (EQM)
From: Jens Axboe
Date: Wed Mar 15 2017 - 11:49:56 EST
On 03/15/2017 06:01 AM, Paolo Valente wrote:
>
>> Il giorno 07 mar 2017, alle ore 18:44, Jens Axboe <axboe@xxxxxxxxx> ha scritto:
>>
>> On 03/04/2017 09:01 AM, Paolo Valente wrote:
>>> @@ -560,6 +600,15 @@ struct bfq_data {
>>> struct bfq_io_cq *bio_bic;
>>> /* bfqq associated with the task issuing current bio for merging */
>>> struct bfq_queue *bio_bfqq;
>>> +
>>> + /*
>>> + * io context to put right after bfqd->lock is released. This
>>> + * filed is used to perform put_io_context, when needed, to
>>> + * after the scheduler lock has been released, and thus
>>> + * prevent an ioc->lock from being possibly taken while the
>>> + * scheduler lock is being held.
>>> + */
>>> + struct io_context *ioc_to_put;
>>> };
>>
>> The logic around this is nasty, effectively you end up having locking
>> around sections of code instea of structures, which is never a good
>> idea.
>>
>> The helper functions for unlocking and dropping the ioc add to the mess
>> as well.
>>
>
> Hi Jens,
> fortunately I seem to have found and fixed the bug causing the failure
> your reported in one of your previous emails, so I've started addressing
> the issue you raise here. But your suggestion below raised doubts
> that I was not able to solve. So I'm bailing out and asking for help.
Great (on fixing that other bug).
>> Can't we simply pass back a pointer to an ioc to free? That should be
>> possible, given that we must have grabbed the bfqd lock ourselves
>> further up in the call chain. So we _know_ that we'll drop it later on.
>> If that wasn't the case, the existing logic wouldn't work.
>>
>
> One of the two functions that discover that an ioc has to bee freed,
> namely __bfq_bfqd_reset_in_service, is invoked at the end of several
> relatively long chains of function invocations. The heads of these
> chains take and release the scheduler lock. One example is:
>
> bfq_dispatch_request -> __bfq_dispatch_request -> bfq_select_queue -> bfq_bfqq_expire -> __bfq_bfqq_expire -> __bfq_bfqd_reset_in_service
>
> To implement your proposal, all the functions involved in these chains
> should be extended to pass back the ioc to put. The resulting, heavy
> version of the code seems really unadvisable, and prone to errors when
> one modifies or adds some chain.
>
> So I have certainly misunderstood something. As usual, to help you
> help me more quickly, here is a summary of what I have understood on
> this matter.
>
> 1. For similar, if not exactly the same, lock-nesting issue related
> to io-context putting, deferred work is used. Probably deferred work
> is used also for other reasons, but for sure it does solve this issue too.
>
> 2. My solution (which I'm not defending; I'm just trying to
> understand) solves the same issue as above: put the io
> context after the other lock is released. But it solves it with no
> work-queueing overhead. Instead of queueing work, it 'queues' the ioc
> to put, and puts it right after releasing the scheduler lock.
>
> Where is my mistake? And what is the correct interpretation of your
> proposal to pass back the pointer (instead of storing it in a field of
> the device data structure)?
I think you understood me correctly. Currently I think the putting of
the io context is somewhat of a mess. You have seemingly random places
where you have to use special unlock functions, to ensure that you
notice that some caller deeper down has set ->ioc_to_put. I took a quick
look at it, and by far most of the cases can return an io_context to
free quite easily. You can mark these functions __must_check to ensure
that we don't drop an io_context, inadvertently. That's already a win
over the random ->ioc_to_put store. And you can then get rid of
bfq_unlock_put_ioc and it's irq variant as well.
The places where you are already returning a value, like off dispatch
for instance, you can just pass in a pointer to an io_context pointer.
If you get this right, it'll be a lot less fragile and hacky than your
current approach.
I'd avoid having to do deferred put from a workqueue at all costs. This
is an _expensive_ operation.
--
Jens Axboe