It looks like list_lru_count() is iterating per node before iterating over all memory
index cddf397..c8ca150 100644In an extreme case, a single invocation of list_lru_walk() can skip all
--- a/fs/dcache.c
+++ b/fs/dcache.c
@@ -1133,10 +1133,11 @@ void shrink_dcache_sb(struct super_block *sb)
LIST_HEAD(dispose);
freed = list_lru_walk(&sb->s_dentry_lru,
- dentry_lru_isolate_shrink, &dispose, UINT_MAX);
+ dentry_lru_isolate_shrink, &dispose, 1024);
this_cpu_sub(nr_dentry_unused, freed);
shrink_dentry_list(&dispose);
+ cond_resched();
} while (freed > 0);
1024 dentries, in which case 'freed' will be 0 forcing us to break the
loop prematurely. I think we should loop until there's at least one
dentry left on the LRU, i.e.
while (list_lru_count(&sb->s_dentry_lru) > 0)
However, even that wouldn't be quite correct, because list_lru_count()
iterates over all memory cgroups to sum list_lru_one->nr_items, which
can race with memcg offlining code migrating dentries off a dead cgroup
(see memcg_drain_all_list_lrus()). So it looks like to make this check
race-free, we need to account the number of entries on the LRU not only
per memcg, but also per node, i.e. add list_lru_node->nr_items.
Fortunately, list_lru entries can't be migrated between NUMA nodes.