Re: [kernel-sched-cputime] question about probable bug in cputime_adjust()
From: Frans Klaver
Date: Wed Jun 28 2017 - 02:03:30 EST
On Wed, Jun 28, 2017 at 7:35 AM, Frans Klaver <fransklaver@xxxxxxxxx> wrote:
> On Wed, Jun 28, 2017 at 1:03 AM, Gustavo A. R. Silva
> <garsilva@xxxxxxxxxxxxxx> wrote:
>>
>> Hello everybody,
>>
>> While looking into Coverity ID 1371643 I ran into the following piece of
>> code at kernel/sched/cputime.c:568:
>>
>> 568/*
>> 569 * Adjust tick based cputime random precision against scheduler runtime
>> 570 * accounting.
>> 571 *
>> 572 * Tick based cputime accounting depend on random scheduling timeslices
>> of a
>> 573 * task to be interrupted or not by the timer. Depending on these
>> 574 * circumstances, the number of these interrupts may be over or
>> 575 * under-optimistic, matching the real user and system cputime with a
>> variable
>> 576 * precision.
>> 577 *
>> 578 * Fix this by scaling these tick based values against the total runtime
>> 579 * accounted by the CFS scheduler.
>> 580 *
>> 581 * This code provides the following guarantees:
>> 582 *
>> 583 * stime + utime == rtime
>> 584 * stime_i+1 >= stime_i, utime_i+1 >= utime_i
>> 585 *
>> 586 * Assuming that rtime_i+1 >= rtime_i.
>> 587 */
>> 588static void cputime_adjust(struct task_cputime *curr,
>> 589 struct prev_cputime *prev,
>> 590 u64 *ut, u64 *st)
>> 591{
>> 592 u64 rtime, stime, utime;
>> 593 unsigned long flags;
>> 594
>> 595 /* Serialize concurrent callers such that we can honour our
>> guarantees */
>> 596 raw_spin_lock_irqsave(&prev->lock, flags);
>> 597 rtime = curr->sum_exec_runtime;
>> 598
>> 599 /*
>> 600 * This is possible under two circumstances:
>> 601 * - rtime isn't monotonic after all (a bug);
>> 602 * - we got reordered by the lock.
>> 603 *
>> 604 * In both cases this acts as a filter such that the rest of the
>> code
>> 605 * can assume it is monotonic regardless of anything else.
>> 606 */
>> 607 if (prev->stime + prev->utime >= rtime)
>> 608 goto out;
>> 609
>> 610 stime = curr->stime;
>> 611 utime = curr->utime;
>> 612
>> 613 /*
>> 614 * If either stime or both stime and utime are 0, assume all
>> runtime is
>> 615 * userspace. Once a task gets some ticks, the monotonicy code at
>> 616 * 'update' will ensure things converge to the observed ratio.
>> 617 */
>> 618 if (stime == 0) {
>> 619 utime = rtime;
>> 620 goto update;
>> 621 }
>> 622
>> 623 if (utime == 0) {
>> 624 stime = rtime;
>> 625 goto update;
>> 626 }
>> 627
>> 628 stime = scale_stime(stime, rtime, stime + utime);
>> 629
>> 630update:
>> 631 /*
>> 632 * Make sure stime doesn't go backwards; this preserves
>> monotonicity
>> 633 * for utime because rtime is monotonic.
>> 634 *
>> 635 * utime_i+1 = rtime_i+1 - stime_i
>> 636 * = rtime_i+1 - (rtime_i - utime_i)
>> 637 * = (rtime_i+1 - rtime_i) + utime_i
>> 638 * >= utime_i
>> 639 */
>> 640 if (stime < prev->stime)
>> 641 stime = prev->stime;
>> 642 utime = rtime - stime;
>> 643
>> 644 /*
>> 645 * Make sure utime doesn't go backwards; this still preserves
>> 646 * monotonicity for stime, analogous argument to above.
>> 647 */
>> 648 if (utime < prev->utime) {
>> 649 utime = prev->utime;
>> 650 stime = rtime - utime;
>> 651 }
>> 652
>> 653 prev->stime = stime;
>> 654 prev->utime = utime;
>> 655out:
>> 656 *ut = prev->utime;
>> 657 *st = prev->stime;
>> 658 raw_spin_unlock_irqrestore(&prev->lock, flags);
>> 659}
>>
>>
>> The issue here is that the value assigned to variable utime at line 619 is
>> overwritten at line 642, which would make such variable assignment useless.
>
> It isn't completely useless, since utime is used in line 628 to calculate stime.
Oh, I missed 'goto update'. Never mind about this one.
>> But I'm suspicious that such assignment is actually correct and that line
>> 642 should be included into the IF block at line 640. Something similar to
>> the following patch:
>>
>> --- a/kernel/sched/cputime.c
>> +++ b/kernel/sched/cputime.c
>> @@ -637,9 +637,10 @@ static void cputime_adjust(struct task_cputime *curr,
>> * = (rtime_i+1 - rtime_i) + utime_i
>> * >= utime_i
>> */
>> - if (stime < prev->stime)
>> + if (stime < prev->stime) {
>> stime = prev->stime;
>> - utime = rtime - stime;
>> + utime = rtime - stime;
>> + }
>>
>>
>> If you confirm this, I will send a patch in a full and proper form.
>>
>> I'd really appreciate your comments.
>
> If you do that, how would you meet the guarantee made in line 583?
>
> Frans