Re: [patch 1/3] tty: resolve tty contention between kernel and user space

[Andy Shevchenko]

On Sun, Jul 9, 2017 at 2:41 PM, Okash Khawaja <okash.khawaja@xxxxxxxxx> wrote:

> +struct tty_struct *tty_kopen(dev_t device)
> +{
> +       struct tty_struct *tty;
> +       struct tty_driver *driver = NULL;
> +       int index = -1;
> +
> +       mutex_lock(&tty_mutex);
> +       driver = tty_lookup_driver(device, NULL, &index);
> +       if (IS_ERR(driver)) {

> +               mutex_unlock(&tty_mutex);
> +               return ERR_CAST(driver);

Hmm... perhaps

tty = ERR_CAST(driver);
goto out_unlock;

See below for further details.

> +       }
> +
> +       /* check whether we're reopening an existing tty */
> +       tty = tty_driver_lookup_tty(driver, NULL, index);
> +       if (IS_ERR(tty))
> +               goto out;
> +
> +       if (tty) {
> +               /* drop kref from tty_driver_lookup_tty() */
> +               tty_kref_put(tty);
> +               tty = ERR_PTR(-EBUSY);
> +       } else { /* tty_init_dev returns tty with the tty_lock held */
> +               tty = tty_init_dev(driver, index);
> +               set_bit(TTY_KOPENED, &tty->flags);
> +       }

> +out:

out_unlock: ?

> +       mutex_unlock(&tty_mutex);
> +       tty_driver_kref_put(driver);

I'm not sure I understand locking model here:

Above
1. take mutex
2. take reference

Here:
1. give mutex back
2. give reference back

I think we usually see symmetrical  calls, i.e.

1. give reference back
2. give mutex back

So, what did I miss?

> +       return tty;
> +}



-- 
With Best Regards,
Andy Shevchenko