Re: [RFC PATCH 2/2] bpf: Initialise mod[] in bpf_trace_printk

From: Daniel Borkmann
Date: Tue Aug 08 2017 - 04:47:05 EST


On 08/08/2017 12:25 AM, James Hogan wrote:
In bpf_trace_printk(), the elements in mod[] are left uninitialised, but
they are then incremented to track the width of the formats. Zero
initialise the array just in case the memory contains non-zero values on
entry.

Fixes: 9c959c863f82 ("tracing: Allow BPF programs to call bpf_trace_printk()")
Signed-off-by: James Hogan <james.hogan@xxxxxxxxxx>
Cc: Alexei Starovoitov <ast@xxxxxxxxxx>
Cc: Daniel Borkmann <daniel@xxxxxxxxxxxxx>
Cc: Steven Rostedt <rostedt@xxxxxxxxxxx>
Cc: Ingo Molnar <mingo@xxxxxxxxxx>
Cc: netdev@xxxxxxxxxxxxxxx
---
When I checked (on MIPS32), the elements tended to have the value zero
anyway (does BPF zero the stack or something clever?), so this is a
purely theoretical fix.
---
kernel/trace/bpf_trace.c | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/kernel/trace/bpf_trace.c b/kernel/trace/bpf_trace.c
index 32dcbe1b48f2..86a52857d941 100644
--- a/kernel/trace/bpf_trace.c
+++ b/kernel/trace/bpf_trace.c
@@ -129,7 +129,7 @@ BPF_CALL_5(bpf_trace_printk, char *, fmt, u32, fmt_size, u64, arg1,
u64, arg2, u64, arg3)
{
bool str_seen = false;
- int mod[3] = {};
+ int mod[3] = { 0, 0, 0 };

I'm probably missing something, but is the behavior of gcc wrt
above initializers different on mips (it zeroes just fine on x86
at least)? If yes, we'd probably need a cocci script to also check
rest of the kernel given this is used in a number of places. Hm,
could you elaborate?

int fmt_cnt = 0;
u64 unsafe_addr;
char buf[64];