+/*
+ * Called once during to boot to initialize boot time.
+ */
+void read_boot_clock64(struct timespec64 *ts)
And because its called only once, it does not need to be marked __init()
and must be kept around forever, right?
+{
+ u64 ns_boot = sched_clock_early(); /* nsec from boot */
Please do not use tail comments. They are a horrible habit.
Instead of adding this crap you'd have better spent time in adding proper
comments explaining the reasoning behind this function,
This is really broken. Look at the time keeping init code. It does:
read_persistent_clock64(&now);
...
read_boot_clock64(&boot);
...
tk_set_xtime(tk, &now);
...
set_normalized_timespec64(&tmp, -boot.tv_sec, -boot.tv_nsec);
tk_set_wall_to_mono(tk, tmp);
Lets assume that the initial read_persistent_clock64() happens right before
the second. For simplicity lets assume we get 1000 seconds since the epoch.
Now read_boot_clock() reads sched_clock_early() which returns 1 second.
The second read_persistent_clock64() returns 1001 seconds since the epoch
because the RTC advanced by now. So the resulting time stamp is going to be
1000s since the epoch.
In case the RTC still returns 100 since the epoch, the resulting time stamp
is 999s since the epoch.
A full second difference. That's time stamp lottery but nothing which we
want to base any boot time analysis on.
You have to come up with something more useful than that.