Re: [PATCH 2/3] early_printk: Add force_early_printk kernel parameter

From: Peter Zijlstra
Date: Thu Oct 12 2017 - 07:40:05 EST


On Thu, Oct 12, 2017 at 12:24:19PM +0200, Petr Mladek wrote:
> On Thu 2017-09-28 14:18:25, Peter Zijlstra wrote:

> > +#ifdef CONFIG_EARLY_PRINTK
> > +struct console *early_console;
> > +
> > +static bool __read_mostly force_early_printk;
> > +
> > +static int __init force_early_printk_setup(char *str)
> > +{
> > + force_early_printk = true;
> > + return 0;
> > +}
> > +early_param("force_early_printk", force_early_printk_setup);
>
> The parameter is currently used only when CONFIG_PRINTK is enabled.
> But CONFIG_EARLY_PRINTK is independent. What would be your preferred
> behavior when CONFIG_PRINTK is disabled, please?

Can we even have !PRINTK && EARLY_PRINTK? If so it seems to me continued
usage of early_printk() is what makes most sense.

> > @@ -1816,6 +1852,11 @@ asmlinkage int vprintk_emit(int facility
> > return vkdb_printf(KDB_MSGSRC_PRINTK, fmt, args);
> > #endif
> >
> > +#ifdef CONFIG_EARLY_PRINTK
> > + if (force_early_printk && early_console)
> > + return early_vprintk(fmt, args);
> > +#endif
> > +
> > if (level == LOGLEVEL_SCHED) {
> > level = LOGLEVEL_DEFAULT;
> > in_sched = true;
> > @@ -1939,7 +1980,12 @@ asmlinkage __visible int printk(const ch
> > int r;
> >
> > va_start(args, fmt);
> > - r = vprintk_func(fmt, args);
> > +#ifdef CONFIG_EARLY_PRINTK
> > + if (force_early_printk && early_console)
> > + r = vprintk_default(fmt, args);
> > + else
> > +#endif
> > + r = vprintk_func(fmt, args);
>
> There is rather theoretical race. We skip vprintk_func() because
> we believe that vprintk_default()/vprintk_emit() would choose
> handle this by early_printk().

Do you mean if someone were to toggle force_early_printk at runtime?

The reason I did it like this and not use that function pointer thing is
that I didn't want to risk anybody hijacking my output ever.