Am Montag, 16. Oktober 2017, 22:50:43 CEST schrieb Daniel Borkmann:
struct task_struct *task = current;
+ task_lock(task);
strncpy(buf, task->comm, size);
+ task_unlock(task);
Wouldn't this potentially lead to a deadlock? E.g. you attach yourself
to task_lock() / spin_lock() / etc, and then the BPF prog triggers the
bpf_get_current_comm() taking the lock again ...
Yes, but doesn't the same apply to the use case when I attach to strncpy()
and run bpf_get_current_comm()?