Re: [PATCH v18 05/10] xbitmap: add more operations

From: Tetsuo Handa
Date: Fri Dec 01 2017 - 08:02:09 EST


Wei Wang wrote:
> On 11/30/2017 06:34 PM, Tetsuo Handa wrote:
> > Wei Wang wrote:
> >> + * @start: the start of the bit range, inclusive
> >> + * @end: the end of the bit range, inclusive
> >> + *
> >> + * This function is used to clear a bit in the xbitmap. If all the bits of the
> >> + * bitmap are 0, the bitmap will be freed.
> >> + */
> >> +void xb_clear_bit_range(struct xb *xb, unsigned long start, unsigned long end)
> >> +{
> >> + struct radix_tree_root *root = &xb->xbrt;
> >> + struct radix_tree_node *node;
> >> + void **slot;
> >> + struct ida_bitmap *bitmap;
> >> + unsigned int nbits;
> >> +
> >> + for (; start < end; start = (start | (IDA_BITMAP_BITS - 1)) + 1) {
> >> + unsigned long index = start / IDA_BITMAP_BITS;
> >> + unsigned long bit = start % IDA_BITMAP_BITS;
> >> +
> >> + bitmap = __radix_tree_lookup(root, index, &node, &slot);
> >> + if (radix_tree_exception(bitmap)) {
> >> + unsigned long ebit = bit + 2;
> >> + unsigned long tmp = (unsigned long)bitmap;
> >> +
> >> + nbits = min(end - start + 1, BITS_PER_LONG - ebit);
> > "nbits = min(end - start + 1," seems to expect that start == end is legal
> > for clearing only 1 bit. But this function is no-op if start == end.
> > Please clarify what "inclusive" intended.
>
> If xb_clear_bit_range(xb,10,10), then it is effectively the same as
> xb_clear_bit(10). Why would it be illegal?
>
> "@start inclusive" means that the @start will also be included to be
> cleared.

If start == end is legal,

for (; start < end; start = (start | (IDA_BITMAP_BITS - 1)) + 1) {

makes this loop do nothing because 10 < 10 is false.



>
> >
> >> +static inline __always_inline void bitmap_clear(unsigned long *map,
> >> + unsigned int start,
> >> + unsigned int nbits)
> >> +{
> >> + if (__builtin_constant_p(nbits) && nbits == 1)
> >> + __clear_bit(start, map);
> >> + else if (__builtin_constant_p(start & 7) && IS_ALIGNED(start, 8) &&
> >> + __builtin_constant_p(nbits & 7) && IS_ALIGNED(nbits, 8))
> > It looks strange to apply __builtin_constant_p test to variables after "& 7".
> >
>
> I think this is normal - if the variables are known at compile time, the
> calculation will be done at compile time (termed constant folding).

I think that

+ else if (__builtin_constant_p(start) && IS_ALIGNED(start, 8) &&
+ __builtin_constant_p(nbits) && IS_ALIGNED(nbits, 8))

is more readable.