Re: [PATCH 2/3, V2] kernel: Move groups_sort to the caller of set_groups.
From: Matthew Wilcox
Date: Tue Dec 05 2017 - 16:29:00 EST
On Tue, Dec 05, 2017 at 07:11:00AM +1100, NeilBrown wrote:
> As we don't seem to be pursuing this possibility is probably isn't very
> important, but I'd like to point out that the original fix isn't a true
> fix.
> It just sorts a shared group_info early. This does not stop corruption.
> Every time a thread calls set_groups() on that group_info it will be
> sorted again.
> The sort algorithm used is the heap sort, and a heap sort always moves
> elements in the array around - it does not leave a sorted array
> untouched (unlike e.g. the quick sort which doesn't move anything in a
> sorted array).
> So it is still possible for two calls to groups_sort() to race.
> We *need* to move groups_sort() out of set_groups().
It must be relatively common to sort an already-sorted array. I wonder
if something like this patch would be worthwhile?
I have deliberately broken this patch so it can't be applied. I haven't
tested it, and for all I know, I got the sign of cmp_func wrong.
diff --git a/lib/sort.c b/lib/sort.c
index d6b7a202b0b6..2b527fde6dad 100644
--- a/lib/sort.c
+++ b/lib/sort.c
@@ -75,7 +75,14 @@ void sort(void *base, size_t num, size_t size,
swap_func = generic_swap;
}
- /* heapify */
+ /* Do not sort an already-sorted array */
+ for (c = 0; c < (n - size); c += size) {
+ if (cmp_func(base + c, base + c + size) < 0)
+ goto heapify;
+ }
+ return;
+
+heapify:
for ( ; i >= 0; i -= size) {
for (r = i; r * 2 + size < n; r = c) {
c = r * 2 + size;