Re: [PATCH] nohz: Fix missing tick reprog while interrupting inline timer softirq

From: Thomas Gleixner
Date: Wed Aug 01 2018 - 13:46:15 EST


On Wed, 1 Aug 2018, Frederic Weisbecker wrote:
> Before updating the full nohz tick or the idle time on IRQ exit, we
> check first if we are not in a nesting interrupt, whether the inner
> interrupt is a hard or a soft IRQ.
>
> There is a historical reason for that: the dyntick idle mode used to
> reprogram the tick on IRQ exit, after softirq processing, and there was
> no point in doing that job in the outer nesting interrupt because the
> tick update will be performed through the end of the inner interrupt
> eventually, with even potential new timer updates.
>
> One corner case could show up though: if an idle tick interrupts a softirq
> executing inline in the idle loop (through a call to local_bh_enable())

Where does this happen? Why is anything in the idle loop doing a
local_bh_disable/enable() pair?

Or are you talking about NOHZ FULL and arbitrary task context?

> after we entered in dynticks mode, the IRQ won't reprogram the tick
> because it assumes the softirq executes on an inner IRQ-tail. As a
> result we might put the CPU in sleep mode with the tick completely
> stopped whereas a timer can still be enqueued. Indeed there is no tick
> reprogramming in local_bh_enable(). We probably asssumed there was no bh
> disabled section in idle, although there didn't seem to be debug code
> ensuring that.
>
> Nowadays the nesting interrupt optimization still stands but only concern
> full dynticks. The tick is stopped on IRQ exit in full dynticks mode
> and we want to wait for the end of the inner IRQ to reprogramm the tick.
> But in_interrupt() doesn't make a difference between softirqs executing
> on IRQ tail and those executing inline. What was to be considered a
> corner case in dynticks-idle mode now becomes a serious opportunity for
> a bug in full dynticks mode: if a tick interrupts a task executing
> softirq inline, the tick reprogramming will be ignored and we may exit
> to userspace after local_bh_enable() with an enqueued timer that will
> never fire.
>
> To fix this, simply keep reprogramming the tick if we are in a hardirq
> interrupting softirq. We can still figure out a way later to restore
> this optimization while excluding inline softirq processing.

I'm not really happy with that 'fix' because what happens if:

....
local_bh_enable()
do_softirq()
--> interrupt()
tick_nohz_irq_exit();
arm_timer();

So if that new timer is the only one on the CPU, what is going to arm the
timer hardware which was just switched off in tick_nohz_irq_exit()?

I haven't looked deep enough, but a simple unconditional call to
tick_irq_exit() at the end of do_softirq() might do the trick.

Thanks,

tglx