Re: [RFC][PATCH 3/3] locking/qspinlock: Optimize for x86

From: Peter Zijlstra
Date: Mon Oct 01 2018 - 16:00:41 EST


On Mon, Oct 01, 2018 at 06:17:00PM +0100, Will Deacon wrote:
> Hi Peter,
>
> Thanks for chewing up my afternoon ;)

I'll get you a beer in EDI ;-)

> On Wed, Sep 26, 2018 at 01:01:20PM +0200, Peter Zijlstra wrote:

> > /**
> > + * set_pending_fetch_acquire - fetch the whole lock value and set pending and locked
> > + * @lock : Pointer to queued spinlock structure
> > + * Return: The previous lock value
> > + *
> > + * *,*,* -> *,1,*
> > + */
> > +static __always_inline u32 set_pending_fetch_acquire(struct qspinlock *lock)
> > +{
> > +#if defined(_Q_NO_FETCH_OR) && _Q_PENDING_BITS == 8
> > + u32 val;
> > +
> > + /*
> > + * For the !LL/SC archs that do not have a native atomic_fetch_or
> > + * but do have a native xchg (x86) we can do trickery and avoid the
> > + * cmpxchg-loop based fetch-or to improve determinism.
> > + *
> > + * We first xchg the pending byte to set PENDING, and then issue a load
> > + * for the rest of the word and mask out the pending byte to compute a
> > + * 'full' value.
> > + */
> > + val = xchg_relaxed(&lock->pending, 1) << _Q_PENDING_OFFSET;
>
> If we make this an xchg_acquire(), can we drop the smp_mb__after_atomic()
> and use a plain atomic_read() to get the rest of the word?

I did consider that; but I confused myself so many times I stuck with
this one. Primarily because on x86 it doesn't matter one way or the
other and smp_mb() are 'easier' to reason about.

> But actually,
> consider this scenario with your patch:
>
> 1. CPU0 sees a locked val, and is about to do your xchg_relaxed() to set
> pending.
>
> 2. CPU1 comes in and sets pending, spins on locked
>
> 3. CPU2 sees a pending and locked val, and is about to enter the head of
> the waitqueue (i.e. it's right before xchg_tail()).
>
> 4. The locked holder unlock()s, CPU1 takes the lock() and then unlock()s
> it, so pending and locked are now 0.
>
> 5. CPU0 sets pending and reads back zeroes for the other fields
>
> 6. CPU0 clears pending and sets locked -- it now has the lock
>
> 7. CPU2 updates tail, sees it's at the head of the waitqueue and spins
> for locked and pending to go clear. However, it reads a stale value
> from step (4) and attempts the atomic_try_cmpxchg() to take the lock.
>
> 8. CPU2 will fail the cmpxchg(), but then go ahead and set locked. At this
> point we're hosed, because both CPU2 and CPU0 have the lock.

Let me draw a picture of that..


CPU0 CPU1 CPU2 CPU3

0) lock
trylock -> (0,0,1)
1)lock
trylock /* fail */

2) lock
trylock /* fail */
tas-pending -> (0,1,1)
wait-locked

3) lock
trylock /* fail */
tas-pending /* fail */

4) unlock -> (0,1,0)
clr_pnd_set_lck -> (0,0,1)
unlock -> (0,0,0)

5) tas-pending -> (0,1,0)
read-val -> (0,1,0)
6) clr_pnd_set_lck -> (0,0,1)
7) xchg_tail -> (n,0,1)
load_acquire <- (n,0,0) (from-4)
8) cmpxchg /* fail */
set_locked()

> Is there something I'm missing that means this can't happen? I suppose
> cacheline granularity ends up giving serialisation between (4) and (7),
> but I'd *much* prefer not to rely on that because it feels horribly
> fragile.

Well, on x86 atomics are fully ordered, so the xchg_tail() does in
fact have smp_mb() in and that should order it sufficient for that not
to happen I think.

But in general, yes ick. Alternatively, making xchg_tail an ACQUIRE
doesn't seem too far out..

> Another idea I was playing with was adding test_and_set_bit_acquire()
> for this, because x86 has an instruction for that, right?

LOCK BTS, yes. So it can do a full 32bit RmW, but it cannot return the
old value of the word, just the old bit (in CF).

I suppose you get rid of the whole mixed size thing, but you still have
the whole two instruction thing.

> > + /*
> > + * Ensures the tail load happens after the xchg().
> > + *
> > + * lock unlock (a)
> > + * xchg ---------------.
> > + * (b) lock unlock +----- fetch_or
> > + * load ---------------'
> > + * lock unlock (c)
> > + *
>
> I failed miserably at parsing this comment :(
>
> I think the main issue is that I don't understand how to read the little
> diagram you've got.

Where fetch_or() is indivisible and has happens-before (a) and
happens-after (c), the new thing is in fact divisible and has
happens-in-between (b).

Of the happens-in-between (b), we can either get a new concurrent
locker, or make progress of an extant concurrent locker because an
unlock happened.

But the rest of the text might indeed be very confused. I think I wrote
the bulk of that when I was in fact doing a xchg16 on locked_pending,
but that's fundamentally broken. I did edit it afterwards, but that
might have just made it worse.