Re: [PATCH 3/6] cpuidle: menu: Get rid of first_idx from menu_select()
From: Rafael J. Wysocki
Date: Thu Oct 04 2018 - 13:19:58 EST
On Thu, Oct 4, 2018 at 4:51 PM Daniel Lezcano <daniel.lezcano@xxxxxxxxxx> wrote:
>
> On Tue, Oct 02, 2018 at 11:44:06PM +0200, Rafael J. Wysocki wrote:
> > From: Rafael J. Wysocki <rafael.j.wysocki@xxxxxxxxx>
> >
> > Rearrange the code in menu_select() so that the loop over idle states
> > always starts from 0 and get rid of the first_idx variable.
> >
> > While at it, add two empty lines to separate conditional statements
> > one another.
> >
> > No intentional behavior changes.
> >
> > Signed-off-by: Rafael J. Wysocki <rafael.j.wysocki@xxxxxxxxx>
> > ---
>
> This code is becoming a bit complex to follow :/
>
> May be I missed something, but it is not possible to enter the condition without
> idx != 0, no ? (I meant the condition if ((drv->states[idx].flags &
> FLAG_POLLING))
Not sure what you mean.
We start with idx = -1, i = 0. If state[0] is enabled, idx becomes 0.
If the target residency or exit latency of state[0] are already beyond
the limits, we just bail out and state[0] will be returned.
If not, we go to i = 1, but idx is still 0. If the target residency
of state[1] is beyond predicted_us (which is the interesting case), we
check (drv->states[0].flags & FLAG_POLLING) and so on.
Currently, the polling state must be state[0] (if used at all) anyway.
> Reviewed-by: Daniel Lezcano <daniel.lezcano@xxxxxxxxxx>
>
Thanks!