On Tue, Dec 11, 2018 at 11:06:43AM +0800, Jason Wang wrote:
On 2018/12/11 äå9:34, Michael S. Tsirkin wrote:Right but it's all slow path - it happens when queue is
On Mon, Dec 10, 2018 at 05:44:52PM +0800, Jason Wang wrote:
When we try to do rx busy polling in tx path in commit 441abde4cd84So rx mutex taken on tx path now. And tx mutex is on rc path ... This
("net: vhost: add rx busy polling in tx path"), we lock rx vq mutex
after tx vq mutex is held. This may lead deadlock so we try to lock vq
one by one in commit 78139c94dc8c ("net: vhost: lock the vqs one by
one"). With this commit, we avoid the deadlock with the assumption
that handle_rx() and handle_tx() run in a same process. But this
commit remove the protection for IOTLB updating which requires the
mutex of each vq to be held.
To solve this issue, the first step is to have a exact same lock
ordering for vhost_net. This is done through:
- For handle_rx(), if busy polling is enabled, lock tx vq immediately.
- For handle_tx(), always lock rx vq before tx vq, and unlock it if
busy polling is not enabled.
- Remove the tricky locking codes in busy polling.
With this, we can have a exact same lock ordering for vhost_net, this
allows us to safely revert commit 78139c94dc8c ("net: vhost: lock the
vqs one by one") in next patch.
The patch will add two more atomic operations on the tx path during
each round of handle_tx(). 1 byte TCP_RR does not notice such
overhead.
Fixes: commit 78139c94dc8c ("net: vhost: lock the vqs one by one")
Cc: Tonghao Zhang<xiangxia.m.yue@xxxxxxxxx>
Signed-off-by: Jason Wang<jasowang@xxxxxxxxxx>
---
drivers/vhost/net.c | 18 +++++++++++++++---
1 file changed, 15 insertions(+), 3 deletions(-)
diff --git a/drivers/vhost/net.c b/drivers/vhost/net.c
index ab11b2bee273..5f272ab4d5b4 100644
--- a/drivers/vhost/net.c
+++ b/drivers/vhost/net.c
@@ -513,7 +513,6 @@ static void vhost_net_busy_poll(struct vhost_net *net,
struct socket *sock;
struct vhost_virtqueue *vq = poll_rx ? tvq : rvq;
- mutex_lock_nested(&vq->mutex, poll_rx ? VHOST_NET_VQ_TX: VHOST_NET_VQ_RX);
vhost_disable_notify(&net->dev, vq);
sock = rvq->private_data;
@@ -543,8 +542,6 @@ static void vhost_net_busy_poll(struct vhost_net *net,
vhost_net_busy_poll_try_queue(net, vq);
else if (!poll_rx) /* On tx here, sock has no rx data. */
vhost_enable_notify(&net->dev, rvq);
-
- mutex_unlock(&vq->mutex);
}
static int vhost_net_tx_get_vq_desc(struct vhost_net *net,
@@ -913,10 +910,16 @@ static void handle_tx_zerocopy(struct vhost_net *net, struct socket *sock)
static void handle_tx(struct vhost_net *net)
{
struct vhost_net_virtqueue *nvq = &net->vqs[VHOST_NET_VQ_TX];
+ struct vhost_net_virtqueue *nvq_rx = &net->vqs[VHOST_NET_VQ_RX];
struct vhost_virtqueue *vq = &nvq->vq;
+ struct vhost_virtqueue *vq_rx = &nvq_rx->vq;
struct socket *sock;
+ mutex_lock_nested(&vq_rx->mutex, VHOST_NET_VQ_RX);
mutex_lock_nested(&vq->mutex, VHOST_NET_VQ_TX);
+ if (!vq->busyloop_timeout)
+ mutex_unlock(&vq_rx->mutex);
+
sock = vq->private_data;
if (!sock)
goto out;
@@ -933,6 +936,8 @@ static void handle_tx(struct vhost_net *net)
handle_tx_copy(net, sock);
out:
+ if (vq->busyloop_timeout)
+ mutex_unlock(&vq_rx->mutex);
mutex_unlock(&vq->mutex);
}
is just messed up. Why can't tx polling drop rx lock before
getting the tx lock and vice versa?
Because we want to poll both tx and rx virtqueue at the same time
(vhost_net_busy_poll()).
ÂÂÂ while (vhost_can_busy_poll(endtime)) {
ÂÂ ÂÂÂ Âif (vhost_has_work(&net->dev)) {
ÂÂ ÂÂÂ ÂÂÂ Â*busyloop_intr = true;
ÂÂ ÂÂÂ ÂÂÂ Âbreak;
ÂÂ ÂÂÂ Â}
ÂÂ ÂÂÂ Âif ((sock_has_rx_data(sock) &&
ÂÂ ÂÂÂ ÂÂÂÂÂ !vhost_vq_avail_empty(&net->dev, rvq)) ||
ÂÂ ÂÂÂ ÂÂÂÂ !vhost_vq_avail_empty(&net->dev, tvq))
ÂÂ ÂÂÂ ÂÂÂ Âbreak;
ÂÂ ÂÂÂ Âcpu_relax();
ÂÂ Â}
And we disable kicks and notification for better performance.
otherwise empty. So this is what I am saying: let's drop the locks
we hold around this.
I'd rather we kept the fine grained locking. E.g. people areOr if we really wanted to force everything to be locked atWe could, but it might requires more changes which could be done for -next I
all times, let's just use a single mutex.
believe.
Thanks
looking at splitting the tx and rx threads. But if not possible
let's fix it cleanly with a coarse-grained one. A mess here will
just create more trouble later.