Re: block: be more careful about status in __bio_chain_endio

From: Mike Snitzer
Date: Fri Feb 22 2019 - 21:44:11 EST


On Fri, Feb 22 2019 at 9:02pm -0500,
John Dorminy <jdorminy@xxxxxxxxxx> wrote:

> I am perhaps not understanding the intricacies here, or not seeing a
> barrier protecting it, so forgive me if I'm off base. I think reading
> parent->bi_status here is unsafe.
> Consider the following sequence of events on two threads.
>
> Thread 0 Thread 1
> In __bio_chain_endio: In __bio_chain_endio:
> [A] Child 0 reads parent->bi_status,
> no error.
> Child bio 1 reads parent, no error seen
> It sets parent->bi_status to an error
> It calls bio_put.
> Child bio 0 calls bio_put
> [end __bio_chain_endio] [end __bio_chain_endio]
> In bio_chain_endio(), bio_endio(parent)
> is called, calling bio_remaining_done()
> which decrements __bi_remaining to 1
> and returns false, so no further endio
> stuff is done.
> In bio_chain_endio(), bio_endio(parent)
> is called, calling bio_remaining_done(),
> decrementing parent->__bi_remaining to
> 0, and continuing to finish parent.
> Either for block tracing or for parent's
> bi_end_io(), this thread tries to read
> parent->bi_status again.
>
> The compiler or the CPU may cache the read from [A], and since there
> are no intervening barriers, parent->bi_status is still believed on
> thread 0 to be success. Thus the bio may still be falsely believed to
> have completed successfully, even though child 1 set an error in it.
>
> Am I missing a subtlety here?

Either neilb's original or even Jens' suggestion would be fine though.

> if (!parent->bi_status && bio->bi_status)
> parent->bi_status = bio->bi_status;

Even if your scenario did play out (which I agree it looks possible)
it'd just degenerate to neilb's version:

> if (bio->bi_status)
> parent->bi_status = bio->bi_status;

Which also accomplishes fixing what Neil originally detailed in his
patch header.