Re: [RFC 2/2] rcutree: Add checks for dynticks counters in rcu_is_cpu_rrupt_from_idle

From: Paul E. McKenney
Date: Sun Mar 24 2019 - 19:43:09 EST


On Fri, Mar 22, 2019 at 11:02:51PM -0400, Joel Fernandes wrote:
> On Fri, Mar 22, 2019 at 09:29:39PM -0400, Joel Fernandes (Google) wrote:
> > In the future we would like to combine the dynticks and dynticks_nesting
> > counters thus leading to simplifying the code. At the moment we cannot
> > do that due to concerns about usermode upcalls appearing to RCU as half
> > of an interrupt. Byungchul tried to do it in [1] but the
> > "half-interrupt" concern was raised. It is half because, what RCU
> > expects is rcu_irq_enter() and rcu_irq_exit() pairs when the usermode
> > exception happens. However, only rcu_irq_enter() is observed. This
> > concern may not be valid anymore, but at least it used to be the case.
> >
> > Out of abundance of caution, Paul added warnings [2] in the RCU code
> > which if not fired by 2021 may allow us to assume that such
> > half-interrupt scenario cannot happen any more, which can lead to
> > simplification of this code.
> >
> > Summary of the changes are the following:
> >
> > (1) In preparation for this combination of counters in the future, we
> > first need to first be sure that rcu_rrupt_from_idle cannot be called
> > from anywhere but a hard-interrupt because previously, the comments
> > suggested otherwise so let us be sure. We discussed this here [3]. We
> > use the services of lockdep to accomplish this.
> >
> > (2) Further rcu_rrupt_from_idle() is not explicit about how it is using
> > the counters which can lead to weird future bugs. This patch therefore
> > makes it more explicit about the specific counter values being tested
> >
> > (3) Lastly, we check for counter underflows just to be sure these are
> > not happening, because the previous code in rcu_rrupt_from_idle() was
> > allowing the case where the counters can underflow, and the function
> > would still return true. Now we are checking for specific values so let
> > us be confident by additional checking, that such underflows don't
> > happen. Any case, if they do, we should fix them and the screaming
> > warning is appropriate. All these checks checks are NOOPs if PROVE_RCU
> > and PROVE_LOCKING are disabled.
> >
> > [1] https://lore.kernel.org/patchwork/patch/952349/
> > [2] Commit e11ec65cc8d6 ("rcu: Add warning to detect half-interrupts")
> > [3] https://lore.kernel.org/lkml/20190312150514.GB249405@xxxxxxxxxx/
> >
> > Cc: byungchul.park@xxxxxxx
> > Cc: kernel-team@xxxxxxxxxxx
> > Cc: rcu@xxxxxxxxxxxxxxx
> > Signed-off-by: Joel Fernandes (Google) <joel@xxxxxxxxxxxxxxxxx>
> > ---
> > kernel/rcu/tree.c | 21 +++++++++++++++++----
> > 1 file changed, 17 insertions(+), 4 deletions(-)
> >
> > diff --git a/kernel/rcu/tree.c b/kernel/rcu/tree.c
> > index 9180158756d2..d94c8ed29f6b 100644
> > --- a/kernel/rcu/tree.c
> > +++ b/kernel/rcu/tree.c
> > @@ -381,16 +381,29 @@ static void __maybe_unused rcu_momentary_dyntick_idle(void)
> > }
> >
> > /**
> > - * rcu_is_cpu_rrupt_from_idle - see if idle or immediately interrupted from idle
> > + * rcu_is_cpu_rrupt_from_idle - see if interrupted from idle
> > *
> > - * If the current CPU is idle or running at a first-level (not nested)
> > + * If the current CPU is idle and running at a first-level (not nested)
> > * interrupt from idle, return true. The caller must have at least
> > * disabled preemption.
> > */
> > static int rcu_is_cpu_rrupt_from_idle(void)
> > {
> > - return __this_cpu_read(rcu_data.dynticks_nesting) <= 0 &&
> > - __this_cpu_read(rcu_data.dynticks_nmi_nesting) <= 1;
> > + /* Called only from within the scheduling-clock interrupt */
> > + lockdep_assert_in_irq();
> > +
> > + /* Check for counter underflows */
> > + RCU_LOCKDEP_WARN(
> > + (__this_cpu_read(rcu_data.dynticks_nesting) < 0) &&
> > + (__this_cpu_read(rcu_data.dynticks_nmi_nesting) < 0),
>
>
> This condition for the warning is supposed to be || instead of &&. Sorry.
>
> Or, I will just use 2 RCU_LOCKDEP_WARN(s) here, that's better.

Also, the dynticks_nmi_nesting being zero is a bug given that we know
we are in an interrupt handler, right? Or am I off by one again?

Thanx, Paul