Re: [PATCH] printk: Do not lose last line in kmsg dump
From: Sergey Senozhatsky
Date: Tue Jul 09 2019 - 06:12:37 EST
On (07/09/19 10:10), Vincent Whitchurch wrote:
> A dump of a 64-byte buffer filled by kmsg_dump_get_buffer(), before this
> patch:
>
> 00000000: 3c 30 3e 5b 20 20 20 20 36 2e 35 32 32 31 39 37 <0>[ 6.522197
> 00000010: 5d 20 41 41 41 41 41 41 41 41 41 41 41 41 41 0a ] AAAAAAAAAAAAA.
> 00000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
> 00000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
>
> After this patch:
>
> 00000000: 3c 30 3e 5b 20 20 20 20 36 2e 34 32 37 35 30 32 <0>[ 6.427502
> 00000010: 5d 20 41 41 41 41 41 41 41 41 41 41 41 41 41 0a ] AAAAAAAAAAAAA.
> 00000020: 3c 30 3e 5b 20 20 20 20 36 2e 34 32 37 37 36 39 <0>[ 6.427769
> 00000030: 5d 20 42 42 42 42 42 42 42 42 31 32 33 34 35 0a ] BBBBBBBB12345.
[..]
> @@ -1318,7 +1318,7 @@ static size_t msg_print_text(const struct printk_log *msg, bool syslog,
> }
>
> if (buf) {
> - if (prefix_len + text_len + 1 >= size - len)
> + if (prefix_len + text_len + 1 > size - len)
> break;
So with this patch the last byte of the buffer is 0xA. It's a bit
uncomfortable that `len', which we return from msg_print_text(),
now points one byte beyond the buffer:
buf[len++] = '\n';
return len;
This is not very common. Not sure what usually happens to kmsg_dump
buffers, but anyone who'd do a rather innocent
kmsg_dump(buf, &len);
buf[len] = 0x00;
will write to something which is not a kmsg buffer (in some cases).
-ss