[PATCH v4 09/14] software node: simplify property_entry_read_string_array()

From: Dmitry Torokhov
Date: Wed Sep 11 2019 - 01:13:21 EST


There is no need to treat string arrays and single strings separately, we can go
exclusively by the element length in relation to data type size.

Signed-off-by: Dmitry Torokhov <dmitry.torokhov@xxxxxxxxx>
---
drivers/base/swnode.c | 21 +++++++--------------
1 file changed, 7 insertions(+), 14 deletions(-)

diff --git a/drivers/base/swnode.c b/drivers/base/swnode.c
index a019b5e90d3b..9c3e566c753e 100644
--- a/drivers/base/swnode.c
+++ b/drivers/base/swnode.c
@@ -173,28 +173,21 @@ static int property_entry_read_string_array(const struct property_entry *props,
const char *propname,
const char **strings, size_t nval)
{
- const struct property_entry *prop;
const void *pointer;
- size_t array_len, length;
+ size_t length;
+ int array_len;

/* Find out the array length. */
- prop = property_entry_get(props, propname);
- if (!prop)
- return -EINVAL;
-
- if (prop->is_array)
- /* Find the length of an array. */
- array_len = property_entry_count_elems_of_size(props, propname,
- sizeof(const char *));
- else
- /* The array length for a non-array string property is 1. */
- array_len = 1;
+ array_len = property_entry_count_elems_of_size(props, propname,
+ sizeof(const char *));
+ if (array_len < 0)
+ return array_len;

/* Return how many there are if strings is NULL. */
if (!strings)
return array_len;

- array_len = min(nval, array_len);
+ array_len = min_t(size_t, nval, array_len);
length = array_len * sizeof(*strings);

pointer = property_entry_find(props, propname, length);
--
2.23.0.162.g0b9fbb3734-goog