Re: [PATCH] iommu/arm-smmu-v3: fix resource_size check

From: Robin Murphy
Date: Thu Jan 09 2020 - 08:23:18 EST


On 26/12/2019 9:50 am, Masahiro Yamada wrote:
This is an off-by-one mistake.

resource_size() returns res->end - res->start + 1.

Heh, despite the optimism of "Avoid one-off errors by introducing a resource_size() function", life finds a way...

Reviewed-by: Robin Murphy <robin.murphy@xxxxxxx>

Signed-off-by: Masahiro Yamada <yamada.masahiro@xxxxxxxxxxxxx>
---

drivers/iommu/arm-smmu-v3.c | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/drivers/iommu/arm-smmu-v3.c b/drivers/iommu/arm-smmu-v3.c
index d9e0d9c19b4f..b463599559d2 100644
--- a/drivers/iommu/arm-smmu-v3.c
+++ b/drivers/iommu/arm-smmu-v3.c
@@ -3599,7 +3599,7 @@ static int arm_smmu_device_probe(struct platform_device *pdev)
/* Base address */
res = platform_get_resource(pdev, IORESOURCE_MEM, 0);
- if (resource_size(res) + 1 < arm_smmu_resource_size(smmu)) {
+ if (resource_size(res) < arm_smmu_resource_size(smmu)) {
dev_err(dev, "MMIO region too small (%pr)\n", res);
return -EINVAL;
}