Paul Cercueil <paul@xxxxxxxxxxxxxxx> writes:
+static u64 notrace ingenic_ost_clocksource_read64(struct clocksource *cs)
+{
+ u32 val1, val2;
+ u64 count, recount;
+ s64 diff;
+
+ /*
+ * The buffering of the upper 32 bits of the timer prevents wrong
+ * results from the bottom 32 bits overflowing due to the timer ticking
+ * along. However, it does not prevent wrong results from simultaneous
+ * reads of the timer, which could reset the buffer mid-read.
+ * Since this kind of wrong read can happen only when the bottom bits
+ * overflow, there will be minutes between wrong reads, so if we read
+ * twice in succession, at least one of the reads will be correct.
+ */
+
+ /* Bypass the regmap here as we must return as soon as possible */
I have a hard time to understand this comment. "Bypass the regmap ..."
and then use a regmap function?
+ regmap_read(ingenic_ost->map, TCU_REG_OST_CNTL, &val1);
+ regmap_read(ingenic_ost->map, TCU_REG_OST_CNTHBUF, &val2);
+ count = (u64)val1 | (u64)val2 << 32;
+
+ regmap_read(ingenic_ost->map, TCU_REG_OST_CNTL, &val1);
+ regmap_read(ingenic_ost->map, TCU_REG_OST_CNTHBUF, &val2);
+ recount = (u64)val1 | (u64)val2 << 32;
+
+ /*
+ * A wrong read will produce a result that is 1<<32 too high: the bottom
+ * part from before overflow and the upper part from after overflow.
+ * Therefore, the lower value of the two reads is the correct value.
+ */
+
+ diff = (s64)(recount - count);
+ if (unlikely(diff < 0))
+ count = recount;
Is this really the right approach here? What is the 64bit readout buying
you?
The timekeeping code can handle a 32bit counter perfectly fine and the
only advantage you get is that your maximum possible idle time will be
longer with a 64bit counter.
But is that really worth the overhead of four MMIO reads versus one in a
hotpath?