Re: [PATCH] nvmem: core: Fix msb clearing bits

From: Mukesh Ojha
Date: Fri Feb 14 2020 - 02:17:20 EST



On 1/31/2020 6:13 PM, Shadab Naseem wrote:
When clearing the msb bits of the resultant buffer, it is
masked with the modulo of the number of bits needed with
respect to the BITS_PER_BYTE. To mask out the buffer,
it is passed though GENMASK of the remainder of the bits
starting from zeroth bit. This case is valid if nbits is not
a multiple of BITS_PER_BYTE and you are actually creating
a GENMASK. If the nbits coming is a multiple of BITS_PER_BYTE,
it would pass a negative value to the high bit number of
GENMASK with zero as the lower bit number.

As per the definition of the GENMASK, the higher bit number (h)
is right operand for bitwise right shift. If the value of the
right operand is negative or is greater or equal to the number
of bits in the promoted left operand, the behavior is undefined.
So passing a negative value to GENMASK could behave differently
across architecture, specifically between 64 and 32 bit.
Also, on passing the hard-coded negative value as GENMASK(-1, 0)
is giving compiler warning for shift-count-overflow.
Hence making a check for clearing the MSB if the nbits are not
a multiple of BITS_PER_BYTE.

Signed-off-by: Shadab Naseem <snaseem@xxxxxxxxxxxxxx>
---
drivers/nvmem/core.c | 3 ++-
1 file changed, 2 insertions(+), 1 deletion(-)

diff --git a/drivers/nvmem/core.c b/drivers/nvmem/core.c
index 1e4a798..23c1547 100644
--- a/drivers/nvmem/core.c
+++ b/drivers/nvmem/core.c
@@ -926,7 +926,8 @@ static void nvmem_shift_read_buffer_in_place(struct nvmem_cell *cell, void *buf)
*p-- = 0;
/* clear msb bits if any leftover in the last byte */
- *p &= GENMASK((cell->nbits%BITS_PER_BYTE) - 1, 0);
+ if (cell->nbits%BITS_PER_BYTE)
+ *p &= GENMASK((cell->nbits%BITS_PER_BYTE) - 1, 0);


LGTM..

Reviewed-by: mojha@xxxxxxxxxxxxxx


Thanks
Mukesh

}
static int __nvmem_cell_read(struct nvmem_device *nvmem,