[PATCH] x86: __memcpy_flushcache: fix wrong alignment if size > 2^32

[Mikulas Patocka]

The statement "min_t(unsigned, size, ALIGN(dest, 8) - dest);" casts both 
arguments to unsigned int and selects the smaller one. However, if the 
size is larger than 2^32, the truncation returns incorrect result.

For example:
	size == 0x100000001, dest == 0x200000002
	min_t(unsigned, size, ALIGN(dest, 8) - dest) == min_t(0x1, 0xe) == 0x1;
	...
	dest += 0x1;
so we copy just one byte and dest remains unaligned.

This patch fixes the bug by replacing unsigned with size_t.

Signed-off-by: Mikulas Patocka <mpatocka@xxxxxxxxxx>

---
 arch/x86/lib/usercopy_64.c |    2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

Index: linux-2.6/arch/x86/lib/usercopy_64.c
===================================================================
--- linux-2.6.orig/arch/x86/lib/usercopy_64.c	2020-04-17 14:06:32.039999000 +0200
+++ linux-2.6/arch/x86/lib/usercopy_64.c	2020-04-17 14:06:32.039999000 +0200
@@ -141,7 +141,7 @@ void __memcpy_flushcache(void *_dst, con
 
 	/* cache copy and flush to align dest */
 	if (!IS_ALIGNED(dest, 8)) {
-		unsigned len = min_t(unsigned, size, ALIGN(dest, 8) - dest);
+		size_t len = min_t(size_t, size, ALIGN(dest, 8) - dest);
 
 		memcpy((void *) dest, (void *) source, len);
 		clean_cache_range((void *) dest, len);